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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 984 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹6500 grow to in 1 year at 25% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
  3. 3.What amount will ₹2000 grow to in 2 years at 25% per year compound interest (in ₹)?
  4. 4.What amount will ₹55900 grow to in 1 year at 25% per year compound interest (in ₹)?
  5. 5.What amount will ₹52300 grow to in 2 years at 10% per year compound interest (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹27300 at 10% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹13600 at 25% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  9. 9.A town has 58800 people. The population grows by 25% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹4000 at 5% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹50400 at 5% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹37200 at 15% per year for 2 years (in ₹)?
  13. 13.What amount will ₹59200 grow to in 2 years at 5% per year compound interest (in ₹)?
  14. 14.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹31100 at 10% per year for 2 years, compounded every year (in ₹).
  16. 16.What amount will ₹33100 grow to in 2 years at 10% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹51800 at 20% per year for 2 years (in ₹)?
  19. 19.A scooter is worth ₹58000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  20. 20.Find the compound interest on ₹26800 at 8% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  22. 22.What amount will ₹26500 grow to in 1 year at 8% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹20700 at 12% per year for 1 year, compounded every year (in ₹).
  24. 24.A scooter is worth ₹17500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  25. 25.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
  26. 26.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
  27. 27.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
  28. 28.What amount will ₹49400 grow to in 1 year at 25% per year compound interest (in ₹)?
  29. 29.A scooter is worth ₹56600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  30. 30.Find the compound interest on ₹20200 at 12% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹40000 grow to in 2 years at 5% per year compound interest (in ₹)?
  32. 32.What amount will ₹16400 grow to in 2 years at 15% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹19200 at 10% per year for 2 years, compounded every year (in ₹).
  34. 34.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  35. 35.Find the compound interest on ₹18200 at 5% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹16400 grow to in 1 year at 8% per year compound interest (in ₹)?
  37. 37.A town has 28800 people. The population grows by 5% every year. What will the population be after 2 years?
  38. 38.A scooter is worth ₹33600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  39. 39.Find the compound interest on ₹2500 at 5% per year for 1 year, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 8125
  2. 2100
  3. 3125
  4. 69875
  5. 63283
  6. 273
  7. 3400
  8. 6305
  9. 91875
  10. 10
  11. 5166
  12. 837
  13. 65268
  14. 60835
  15. 6531
  16. 40051
  17. 657
  18. 2072
  19. 41905
  20. 2144
  21. 540
  22. 28620
  23. 2484
  24. 13552
  25. 55404
  26. 58320
  27. 34496
  28. 61750
  29. 45280
  30. 2424
  31. 44100
  32. 21689
  33. 4032
  34. 41154
  35. 910
  36. 17712
  37. 31752
  38. 28560
  39. 125
  40. 3180

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