Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 99 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹4700 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
3. 3.What amount will ₹25000 grow to in 3 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹8300 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹8800 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹29500 at 20% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹3400 grow to in 1 year at 8% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹32800 at 15% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹22400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
12. 12.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹40800 at 5% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹12100 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.A scooter is worth ₹48100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹10100 at 20% per year for 2 years (in ₹)?
18. 18.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
19. 19.What amount will ₹30300 grow to in 1 year at 12% per year compound interest (in ₹)?
20. 20.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
21. 21.Find the compound interest on ₹17100 at 12% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹44400 at 15% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹52300 at 8% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
27. 27.A scooter is worth ₹7600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
28. 28.What amount will ₹48400 grow to in 2 years at 10% per year compound interest (in ₹)?
29. 29.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
30. 30.What amount will ₹20200 grow to in 2 years at 10% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹25000 at 10% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹9200 at 15% per year for 2 years (in ₹)?
33. 33.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
37. 37.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
40. 40.A scooter is worth ₹25900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets