Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹58200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 2.A town has 7500 people. The population grows by 15% every year. What will the population be after 1 year?
- 3.Find the compound interest on ₹54800 at 10% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 5.A town has 47500 people. The population grows by 20% every year. What will the population be after 3 years?
- 6.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
- 7.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
- 8.A town has 30200 people. The population grows by 8% every year. What will the population be after 1 year?
- 9.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹58100 at 10% per year for 2 years (in ₹)?
- 12.A scooter is worth ₹52000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 13.A scooter is worth ₹3500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 14.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 15.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹13200 at 10% per year for 2 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹55200 at 5% per year for 2 years, compounded every year (in ₹).
- 20.What amount will ₹15500 grow to in 1 year at 12% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
- 22.What amount will ₹16800 grow to in 1 year at 8% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹23300 at 4% per year for 1 year, compounded every year (in ₹).
- 25.A town has 57000 people. The population grows by 12% every year. What will the population be after 1 year?
- 26.What is the difference between the compound interest and the simple interest on ₹30700 at 20% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
- 28.What amount will ₹50400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 29.What amount will ₹32800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹36300 at 20% per year for 2 years (in ₹)?
- 31.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
- 32.A town has 3500 people. The population grows by 10% every year. What will the population be after 2 years?
- 33.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 34.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
- 37.A scooter is worth ₹56300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 38.Find the compound interest on ₹13200 at 5% per year for 2 years, compounded every year (in ₹).
- 39.A town has 24700 people. The population grows by 10% every year. What will the population be after 2 years?
- 40.What is the difference between the compound interest and the simple interest on ₹35000 at 10% per year for 2 years (in ₹)?
Answer key
- 52380
- 8625
- 5480
- 416
- 82080
- 15972
- 18816
- 32616
- 208
- 8100
- 581
- 37908
- 2240
- 40656
- 5724
- 16668
- 4575
- 2772
- 5658
- 17360
- 61
- 18144
- 8334
- 932
- 63840
- 1228
- 648
- 72576
- 43378
- 1452
- 78125
- 4235
- 29478
- 62720
- 4452
- 8268
- 45040
- 1353
- 29887
- 350
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