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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 992 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A scooter is worth ₹58200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  2. 2.A town has 7500 people. The population grows by 15% every year. What will the population be after 1 year?
  3. 3.Find the compound interest on ₹54800 at 10% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
  5. 5.A town has 47500 people. The population grows by 20% every year. What will the population be after 3 years?
  6. 6.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
  7. 7.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
  8. 8.A town has 30200 people. The population grows by 8% every year. What will the population be after 1 year?
  9. 9.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹58100 at 10% per year for 2 years (in ₹)?
  12. 12.A scooter is worth ₹52000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  13. 13.A scooter is worth ₹3500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  14. 14.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  15. 15.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹13200 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹55200 at 5% per year for 2 years, compounded every year (in ₹).
  20. 20.What amount will ₹15500 grow to in 1 year at 12% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
  22. 22.What amount will ₹16800 grow to in 1 year at 8% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹23300 at 4% per year for 1 year, compounded every year (in ₹).
  25. 25.A town has 57000 people. The population grows by 12% every year. What will the population be after 1 year?
  26. 26.What is the difference between the compound interest and the simple interest on ₹30700 at 20% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  28. 28.What amount will ₹50400 grow to in 2 years at 20% per year compound interest (in ₹)?
  29. 29.What amount will ₹32800 grow to in 2 years at 15% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹36300 at 20% per year for 2 years (in ₹)?
  31. 31.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
  32. 32.A town has 3500 people. The population grows by 10% every year. What will the population be after 2 years?
  33. 33.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  34. 34.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
  37. 37.A scooter is worth ₹56300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  38. 38.Find the compound interest on ₹13200 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.A town has 24700 people. The population grows by 10% every year. What will the population be after 2 years?
  40. 40.What is the difference between the compound interest and the simple interest on ₹35000 at 10% per year for 2 years (in ₹)?

Answer key

  1. 52380
  2. 8625
  3. 5480
  4. 416
  5. 82080
  6. 15972
  7. 18816
  8. 32616
  9. 208
  10. 8100
  11. 581
  12. 37908
  13. 2240
  14. 40656
  15. 5724
  16. 16668
  17. 4575
  18. 2772
  19. 5658
  20. 17360
  21. 61
  22. 18144
  23. 8334
  24. 932
  25. 63840
  26. 1228
  27. 648
  28. 72576
  29. 43378
  30. 1452
  31. 78125
  32. 4235
  33. 29478
  34. 62720
  35. 4452
  36. 8268
  37. 45040
  38. 1353
  39. 29887
  40. 350

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