Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 994 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹29900 at 20% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 21300 people. The population grows by 4% every year. What will the population be after 1 year?
6. 6.A scooter is worth ₹21600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹9600 at 20% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹7400 at 20% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹21400 at 20% per year for 2 years (in ₹)?
12. 12.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
13. 13.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹29700 at 15% per year for 1 year, compounded every year (in ₹).
15. 15.A scooter is worth ₹27500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
16. 16.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹23900 at 20% per year for 1 year, compounded every year (in ₹).
19. 19.A scooter is worth ₹17200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹47700 at 4% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
22. 22.What amount will ₹49500 grow to in 3 years at 20% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
25. 25.What amount will ₹13800 grow to in 1 year at 25% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹38800 at 20% per year for 2 years (in ₹)?
28. 28.What amount will ₹37000 grow to in 1 year at 25% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹21800 at 10% per year for 2 years, compounded every year (in ₹).
30. 30.A scooter is worth ₹14900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
31. 31.What amount will ₹52300 grow to in 1 year at 20% per year compound interest (in ₹)?
32. 32.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
34. 34.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
35. 35.A town has 20400 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹55900 at 10% per year for 1 year, compounded every year (in ₹).
37. 37.A town has 48300 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.What amount will ₹51600 grow to in 2 years at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹45000 at 20% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?

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