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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 999 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
  2. 2.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  3. 3.A scooter is worth ₹36900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹59200 at 15% per year for 2 years (in ₹)?
  6. 6.What amount will ₹49200 grow to in 2 years at 25% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹31500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  8. 8.A town has 4500 people. The population grows by 25% every year. What will the population be after 1 year?
  9. 9.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
  11. 11.What amount will ₹32000 grow to in 3 years at 10% per year compound interest (in ₹)?
  12. 12.What amount will ₹11200 grow to in 2 years at 5% per year compound interest (in ₹)?
  13. 13.What amount will ₹53400 grow to in 1 year at 10% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹56100 at 5% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
  17. 17.A town has 29700 people. The population grows by 25% every year. What will the population be after 1 year?
  18. 18.What amount will ₹32100 grow to in 2 years at 20% per year compound interest (in ₹)?
  19. 19.A scooter is worth ₹18200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  20. 20.A town has 53200 people. The population grows by 25% every year. What will the population be after 2 years?
  21. 21.What is the difference between the compound interest and the simple interest on ₹13600 at 5% per year for 2 years (in ₹)?
  22. 22.A scooter is worth ₹2900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What amount will ₹47600 grow to in 1 year at 20% per year compound interest (in ₹)?
  24. 24.What amount will ₹57600 grow to in 2 years at 25% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  26. 26.Find the compound interest on ₹3200 at 8% per year for 1 year, compounded every year (in ₹).
  27. 27.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹32000 at 20% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹49200 at 15% per year for 2 years, compounded every year (in ₹).
  30. 30.What amount will ₹16900 grow to in 1 year at 20% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
  32. 32.A scooter is worth ₹19300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What amount will ₹7700 grow to in 1 year at 4% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  35. 35.A town has 48000 people. The population grows by 25% every year. What will the population be after 3 years?
  36. 36.What is the difference between the compound interest and the simple interest on ₹26800 at 25% per year for 2 years (in ₹)?
  37. 37.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  38. 38.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  39. 39.A town has 19500 people. The population grows by 20% every year. What will the population be after 1 year?
  40. 40.Find the compound interest on ₹5200 at 5% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 11
  2. 9261
  3. 29520
  4. 16
  5. 1332
  6. 76875
  7. 16128
  8. 5625
  9. 55404
  10. 25
  11. 42592
  12. 12348
  13. 58740
  14. 2805
  15. 64827
  16. 125
  17. 37125
  18. 46224
  19. 14742
  20. 83125
  21. 34
  22. 2465
  23. 57120
  24. 90000
  25. 3872
  26. 256
  27. 49572
  28. 6400
  29. 15867
  30. 20280
  31. 2979
  32. 15633
  33. 8008
  34. 176
  35. 93750
  36. 1675
  37. 12167
  38. 36
  39. 23400
  40. 533

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