Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹21200 at 5% per year for 2 years (in ₹)?
- 2.What amount will ₹33000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹44900 at 8% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹42800 at 5% per year for 1 year, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
- 8.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹44000 at 25% per year for 2 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 12.What amount will ₹28400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹42000 at 25% per year for 2 years (in ₹)?
- 14.What amount will ₹45000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹54800 at 15% per year for 1 year, compounded every year (in ₹).
- 16.A town has 50000 people. The population grows by 25% every year. What will the population be after 2 years?
- 17.Find the compound interest on ₹40000 at 10% per year for 3 years, compounded every year (in ₹).
- 18.A scooter is worth ₹48500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 19.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 20.A town has 30300 people. The population grows by 25% every year. What will the population be after 1 year?
- 21.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 22.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
- 23.What amount will ₹54500 grow to in 1 year at 4% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
- 25.A town has 6200 people. The population grows by 12% every year. What will the population be after 1 year?
- 26.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹31200 at 10% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹10400 at 25% per year for 2 years (in ₹)?
- 29.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 30.A town has 7500 people. The population grows by 8% every year. What will the population be after 2 years?
- 31.What amount will ₹9300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 32.A town has 59900 people. The population grows by 8% every year. What will the population be after 1 year?
- 33.A town has 31600 people. The population grows by 5% every year. What will the population be after 1 year?
- 34.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 35.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
- 36.A scooter is worth ₹14600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 37.A town has 9100 people. The population grows by 10% every year. What will the population be after 2 years?
- 38.What is the difference between the compound interest and the simple interest on ₹11100 at 20% per year for 2 years (in ₹)?
- 39.What amount will ₹48400 grow to in 1 year at 10% per year compound interest (in ₹)?
- 40.What amount will ₹14000 grow to in 2 years at 25% per year compound interest (in ₹)?
Answer key
- 53
- 36300
- 20
- 3592
- 5958
- 2140
- 120
- 15680
- 24750
- 84
- 41154
- 29820
- 2625
- 77760
- 8220
- 78125
- 13240
- 46560
- 16224
- 37875
- 9261
- 72128
- 56680
- 127
- 6944
- 22875
- 312
- 650
- 37632
- 8748
- 11625
- 64692
- 33180
- 17496
- 37044
- 14016
- 11011
- 444
- 53240
- 21875
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