Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹32700 grow to in 1 year at 12% per year compound interest (in ₹)?
- 2.A town has 16000 people. The population grows by 25% every year. What will the population be after 1 year?
- 3.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
- 4.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 6.What amount will ₹21200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 7.A town has 27500 people. The population grows by 4% every year. What will the population be after 2 years?
- 8.A scooter is worth ₹17600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 9.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
- 10.What is the difference between the compound interest and the simple interest on ₹30800 at 15% per year for 2 years (in ₹)?
- 11.A scooter is worth ₹53200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 12.What amount will ₹37600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 13.What amount will ₹3600 grow to in 1 year at 20% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹45200 at 5% per year for 2 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹36800 at 20% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹22700 at 5% per year for 1 year, compounded every year (in ₹).
- 17.What amount will ₹43000 grow to in 1 year at 25% per year compound interest (in ₹)?
- 18.A scooter is worth ₹47500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 19.What amount will ₹55200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 20.What amount will ₹10000 grow to in 2 years at 10% per year compound interest (in ₹)?
- 21.A town has 46500 people. The population grows by 20% every year. What will the population be after 3 years?
- 22.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
- 23.Find the compound interest on ₹3000 at 20% per year for 1 year, compounded every year (in ₹).
- 24.Find the compound interest on ₹46400 at 4% per year for 1 year, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
- 26.A town has 37100 people. The population grows by 20% every year. What will the population be after 1 year?
- 27.Find the compound interest on ₹58400 at 20% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹52100 at 12% per year for 1 year, compounded every year (in ₹).
- 29.What amount will ₹55200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 30.A scooter is worth ₹42900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 31.A town has 13600 people. The population grows by 12% every year. What will the population be after 1 year?
- 32.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
- 35.What amount will ₹31600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 36.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹6500 at 20% per year for 2 years (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹30800 at 25% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹21000 at 20% per year for 2 years (in ₹)?
Answer key
- 36624
- 20000
- 16224
- 684
- 20
- 28037
- 29744
- 15488
- 87500
- 693
- 50540
- 41454
- 4320
- 4633
- 1472
- 1135
- 53750
- 43776
- 59616
- 12100
- 80352
- 35152
- 600
- 1856
- 52
- 44520
- 25696
- 6252
- 57960
- 34320
- 15232
- 80
- 24
- 60
- 34839
- 64896
- 260
- 1925
- 7632
- 840
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets