Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹32100 at 10% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹21200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 3.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹49300 at 12% per year for 1 year, compounded every year (in ₹).
- 6.What amount will ₹58000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 7.A scooter is worth ₹15000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 8.What amount will ₹48400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 9.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 10.What amount will ₹6300 grow to in 2 years at 20% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹32800 at 15% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹56800 at 15% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹48600 at 20% per year for 2 years, compounded every year (in ₹).
- 14.Find the compound interest on ₹15000 at 20% per year for 3 years, compounded every year (in ₹).
- 15.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 16.A town has 57500 people. The population grows by 4% every year. What will the population be after 2 years?
- 17.A scooter is worth ₹37500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 18.What amount will ₹29200 grow to in 1 year at 15% per year compound interest (in ₹)?
- 19.What amount will ₹5400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹49600 at 25% per year for 2 years, compounded every year (in ₹).
- 22.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹32400 at 15% per year for 2 years (in ₹)?
- 24.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
- 25.Find the compound interest on ₹40400 at 4% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹40000 at 25% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹5900 at 15% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹49600 at 25% per year for 1 year, compounded every year (in ₹).
- 30.Find the compound interest on ₹37900 at 15% per year for 1 year, compounded every year (in ₹).
- 31.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
- 32.A town has 20000 people. The population grows by 10% every year. What will the population be after 3 years?
- 33.Find the compound interest on ₹41900 at 5% per year for 1 year, compounded every year (in ₹).
- 34.A scooter is worth ₹57200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 35.A town has 11700 people. The population grows by 12% every year. What will the population be after 1 year?
- 36.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹52600 at 20% per year for 1 year, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 39.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 40.Find the compound interest on ₹3800 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 321
- 16960
- 49247
- 792
- 5916
- 64960
- 11250
- 75625
- 37908
- 9072
- 10578
- 18318
- 21384
- 10920
- 12167
- 62192
- 29040
- 33580
- 6480
- 816
- 27900
- 18522
- 729
- 27783
- 1616
- 1272
- 38125
- 885
- 12400
- 5685
- 14560
- 26620
- 2095
- 32175
- 13104
- 37044
- 10520
- 336
- 20700
- 798
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