Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A town has 28200 people. The population grows by 15% every year. What will the population be after 1 year?
- 2.What amount will ₹42400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹7200 at 5% per year for 2 years, compounded every year (in ₹).
- 4.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 5.What amount will ₹16500 grow to in 1 year at 15% per year compound interest (in ₹)?
- 6.A scooter is worth ₹49600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹2500 at 20% per year for 3 years, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹16000 at 20% per year for 3 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹55600 at 5% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹43900 at 15% per year for 1 year, compounded every year (in ₹).
- 14.Find the compound interest on ₹36100 at 10% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹21200 at 8% per year for 1 year, compounded every year (in ₹).
- 17.A scooter is worth ₹6800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹52800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 20.A scooter is worth ₹7700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 21.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 22.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹26900 at 20% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹13600 at 20% per year for 2 years (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹56300 at 8% per year for 1 year, compounded every year (in ₹).
- 27.What amount will ₹39600 grow to in 2 years at 20% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹53600 at 25% per year for 2 years, compounded every year (in ₹).
- 29.What amount will ₹29000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹26600 at 10% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹33900 at 10% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
- 34.What amount will ₹28700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 35.A scooter is worth ₹22400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹52400 at 25% per year for 2 years (in ₹)?
- 37.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
- 38.What amount will ₹58500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹33500 at 5% per year for 1 year, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
Answer key
- 32430
- 66250
- 738
- 48013
- 18975
- 20925
- 475
- 1820
- 16
- 11648
- 9540
- 139
- 6585
- 3610
- 63
- 1696
- 3825
- 144
- 39600
- 7084
- 7744
- 56425
- 1076
- 544
- 2150
- 4504
- 57024
- 30150
- 33350
- 266
- 5408
- 339
- 612
- 34440
- 9450
- 3275
- 11664
- 70785
- 1675
- 148
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