Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 110 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹32000 at 15% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
3. 3.A scooter is worth ₹12500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
4. 4.What amount will ₹57600 grow to in 2 years at 5% per year compound interest (in ₹)?
5. 5.A scooter is worth ₹15000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
6. 6.What amount will ₹12000 grow to in 3 years at 20% per year compound interest (in ₹)?
7. 7.What amount will ₹15200 grow to in 2 years at 15% per year compound interest (in ₹)?
8. 8.What amount will ₹7200 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹9600 at 5% per year for 2 years (in ₹)?
10. 10.What amount will ₹27200 grow to in 1 year at 12% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹9600 at 25% per year for 2 years (in ₹)?
12. 12.A town has 25800 people. The population grows by 25% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹11000 at 10% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹55200 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
16. 16.A town has 53700 people. The population grows by 25% every year. What will the population be after 1 year?
17. 17.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹38800 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A scooter is worth ₹14000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
20. 20.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
21. 21.A town has 14400 people. The population grows by 25% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹49600 at 25% per year for 2 years (in ₹)?
23. 23.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹4800 at 5% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹29200 at 25% per year for 2 years (in ₹)?
28. 28.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
29. 29.What amount will ₹5900 grow to in 1 year at 12% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹32700 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
32. 32.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
33. 33.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹12000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
36. 36.A scooter is worth ₹35200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹30100 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹20300 at 20% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹34800 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹13500 at 20% per year for 1 year, compounded every year (in ₹).

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