Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 111 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹41200 at 25% per year for 2 years (in ₹)?
2. 2.A town has 43100 people. The population grows by 20% every year. What will the population be after 1 year?
3. 3.What is the difference between the compound interest and the simple interest on ₹12000 at 20% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
5. 5.What amount will ₹27700 grow to in 1 year at 8% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹9800 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹38800 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹43200 at 15% per year for 2 years (in ₹)?
9. 9.A town has 37800 people. The population grows by 4% every year. What will the population be after 1 year?
10. 10.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹3600 at 25% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹49600 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.A town has 11900 people. The population grows by 10% every year. What will the population be after 1 year?
14. 14.What is the difference between the compound interest and the simple interest on ₹30800 at 5% per year for 2 years (in ₹)?
15. 15.A scooter is worth ₹18300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
16. 16.What amount will ₹36000 grow to in 2 years at 15% per year compound interest (in ₹)?
17. 17.What amount will ₹37900 grow to in 1 year at 15% per year compound interest (in ₹)?
18. 18.A scooter is worth ₹52900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
19. 19.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
20. 20.What amount will ₹31200 grow to in 2 years at 15% per year compound interest (in ₹)?
21. 21.A town has 56000 people. The population grows by 15% every year. What will the population be after 2 years?
22. 22.Find the compound interest on ₹52300 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹21200 at 5% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹42900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹8800 at 5% per year for 2 years (in ₹)?
26. 26.A scooter is worth ₹29600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹44400 at 15% per year for 2 years (in ₹)?
28. 28.A town has 45900 people. The population grows by 20% every year. What will the population be after 2 years?
29. 29.A scooter is worth ₹11900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
30. 30.What amount will ₹3500 grow to in 1 year at 20% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹44400 at 5% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
33. 33.What amount will ₹51200 grow to in 1 year at 5% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹56500 at 20% per year for 3 years, compounded every year (in ₹).
35. 35.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
36. 36.What amount will ₹38400 grow to in 3 years at 25% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
38. 38.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
39. 39.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
40. 40.Find the compound interest on ₹3400 at 12% per year for 1 year, compounded every year (in ₹).

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