Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 112 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹45100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
2. 2.A town has 59200 people. The population grows by 10% every year. What will the population be after 2 years?
3. 3.A town has 31200 people. The population grows by 8% every year. What will the population be after 1 year?
4. 4.A town has 17900 people. The population grows by 25% every year. What will the population be after 1 year?
5. 5.A town has 28200 people. The population grows by 10% every year. What will the population be after 2 years?
6. 6.A town has 9300 people. The population grows by 20% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹25300 at 5% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹51200 at 5% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹41600 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.A town has 47800 people. The population grows by 4% every year. What will the population be after 1 year?
12. 12.Find the compound interest on ₹45100 at 20% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹25200 at 15% per year for 2 years, compounded every year (in ₹).
14. 14.Find the compound interest on ₹54000 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹28800 grow to in 1 year at 5% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹40900 at 25% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹8000 grow to in 1 year at 10% per year compound interest (in ₹)?
18. 18.A town has 59100 people. The population grows by 4% every year. What will the population be after 1 year?
19. 19.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
20. 20.What amount will ₹20600 grow to in 1 year at 10% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹18900 at 20% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
23. 23.What amount will ₹57500 grow to in 2 years at 8% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹42500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
25. 25.What amount will ₹57000 grow to in 1 year at 4% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹3300 at 10% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹39900 at 12% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
29. 29.What amount will ₹54800 grow to in 1 year at 20% per year compound interest (in ₹)?
30. 30.What amount will ₹45900 grow to in 1 year at 8% per year compound interest (in ₹)?
31. 31.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
32. 32.A town has 38400 people. The population grows by 25% every year. What will the population be after 2 years?
33. 33.What amount will ₹47200 grow to in 1 year at 8% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
35. 35.What amount will ₹12800 grow to in 2 years at 15% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹27000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
37. 37.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
38. 38.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹53000 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹22100 at 15% per year for 1 year, compounded every year (in ₹).

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