Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 55000 people. The population grows by 10% every year. What will the population be after 3 years?
- 2.What amount will ₹8000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
- 4.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 5.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
- 6.A scooter is worth ₹20000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 7.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 8.A scooter is worth ₹20000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 9.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹21200 at 25% per year for 1 year, compounded every year (in ₹).
- 12.Find the compound interest on ₹48000 at 10% per year for 3 years, compounded every year (in ₹).
- 13.What amount will ₹42200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
- 15.A scooter is worth ₹47000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 16.A scooter is worth ₹22000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 17.What amount will ₹20800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 18.What amount will ₹56200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 19.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 21.A town has 48900 people. The population grows by 5% every year. What will the population be after 1 year?
- 22.What amount will ₹51300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
- 24.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 25.A scooter is worth ₹24000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹13200 at 15% per year for 2 years (in ₹)?
- 28.What amount will ₹14800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹45000 at 5% per year for 1 year, compounded every year (in ₹).
- 30.What amount will ₹54800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 31.A town has 57600 people. The population grows by 25% every year. What will the population be after 3 years?
- 32.A scooter is worth ₹10800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 33.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹28000 at 20% per year for 3 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹20000 at 15% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹30000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 37.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 38.A town has 38700 people. The population grows by 10% every year. What will the population be after 2 years?
- 39.What is the difference between the compound interest and the simple interest on ₹3200 at 10% per year for 2 years (in ₹)?
- 40.A town has 6300 people. The population grows by 15% every year. What will the population be after 1 year?
Answer key
- 73205
- 8640
- 14628
- 15625
- 64827
- 11250
- 4167
- 16928
- 29744
- 20
- 5300
- 15888
- 52750
- 12200
- 34263
- 16038
- 40625
- 70250
- 26244
- 416
- 51345
- 56430
- 6289
- 69984
- 21120
- 1278
- 297
- 16317
- 2250
- 61376
- 112500
- 7803
- 408
- 20384
- 450
- 25392
- 20835
- 46827
- 32
- 7245
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