Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 122 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹22800 grow to in 2 years at 15% per year compound interest (in ₹)?
2. 2.A town has 11800 people. The population grows by 20% every year. What will the population be after 2 years?
3. 3.What amount will ₹23300 grow to in 2 years at 10% per year compound interest (in ₹)?
4. 4.A scooter is worth ₹33800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
5. 5.Find the compound interest on ₹42900 at 12% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹14600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹38800 at 15% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹49300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
13. 13.A scooter is worth ₹37200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹16200 at 25% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹45000 at 8% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹48400 at 20% per year for 2 years (in ₹)?
17. 17.A scooter is worth ₹16800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
18. 18.A town has 20000 people. The population grows by 4% every year. What will the population be after 2 years?
19. 19.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹47000 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹14400 at 5% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹13100 at 10% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
24. 24.What amount will ₹27000 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹14600 at 10% per year for 2 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹21600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
27. 27.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
28. 28.A scooter is worth ₹5000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
29. 29.What amount will ₹53000 grow to in 1 year at 25% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹13400 at 4% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹36100 at 10% per year for 2 years (in ₹)?
32. 32.What amount will ₹17200 grow to in 2 years at 25% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹12400 at 25% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹40500 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
36. 36.A town has 20000 people. The population grows by 8% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹31600 at 25% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?

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