Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 123 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹42800 grow to in 2 years at 15% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
3. 3.A town has 13000 people. The population grows by 10% every year. What will the population be after 3 years?
4. 4.Find the compound interest on ₹29900 at 10% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹57000 at 20% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹2000 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹8400 at 20% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹51400 at 20% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹18000 at 8% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹10000 at 15% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹15200 at 20% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹23600 at 15% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹57800 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹54300 at 4% per year for 1 year, compounded every year (in ₹).
19. 19.What amount will ₹31900 grow to in 2 years at 20% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹8700 at 20% per year for 2 years (in ₹)?
21. 21.A town has 44200 people. The population grows by 10% every year. What will the population be after 1 year?
22. 22.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
23. 23.A town has 56300 people. The population grows by 20% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹39200 at 15% per year for 2 years (in ₹)?
26. 26.A scooter is worth ₹55000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
27. 27.A town has 26600 people. The population grows by 20% every year. What will the population be after 2 years?
28. 28.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).
29. 29.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.What amount will ₹15200 grow to in 1 year at 15% per year compound interest (in ₹)?
31. 31.What amount will ₹48400 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹41200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
33. 33.A scooter is worth ₹11700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
34. 34.What amount will ₹56200 grow to in 1 year at 10% per year compound interest (in ₹)?
35. 35.What amount will ₹38800 grow to in 1 year at 5% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹13000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
37. 37.Find the compound interest on ₹44100 at 25% per year for 1 year, compounded every year (in ₹).
38. 38.A scooter is worth ₹49200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
39. 39.A town has 3300 people. The population grows by 8% every year. What will the population be after 1 year?
40. 40.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?

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