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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 134 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 57000 people. The population grows by 4% every year. What will the population be after 1 year?
  2. 2.Find the compound interest on ₹39900 at 8% per year for 1 year, compounded every year (in ₹).
  3. 3.What amount will ₹56800 grow to in 1 year at 20% per year compound interest (in ₹)?
  4. 4.What amount will ₹21400 grow to in 1 year at 10% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹54100 at 20% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹58400 at 25% per year for 2 years (in ₹)?
  8. 8.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
  9. 9.What amount will ₹17300 grow to in 2 years at 10% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹40400 at 25% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹2000 at 20% per year for 3 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹14200 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.What amount will ₹54800 grow to in 1 year at 15% per year compound interest (in ₹)?
  15. 15.A town has 12900 people. The population grows by 8% every year. What will the population be after 1 year?
  16. 16.Find the compound interest on ₹2600 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹49500 at 20% per year for 3 years, compounded every year (in ₹).
  18. 18.What amount will ₹41600 grow to in 1 year at 25% per year compound interest (in ₹)?
  19. 19.What amount will ₹15300 grow to in 1 year at 12% per year compound interest (in ₹)?
  20. 20.What amount will ₹27800 grow to in 2 years at 20% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹37700 at 10% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹52600 at 10% per year for 2 years, compounded every year (in ₹).
  23. 23.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  24. 24.What amount will ₹11200 grow to in 1 year at 4% per year compound interest (in ₹)?
  25. 25.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹48500 at 20% per year for 3 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  29. 29.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
  30. 30.A scooter is worth ₹48000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  31. 31.A scooter is worth ₹19000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹20400 at 15% per year for 2 years (in ₹)?
  33. 33.A town has 28400 people. The population grows by 5% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹7400 at 10% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹26000 at 15% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹13700 at 8% per year for 1 year, compounded every year (in ₹).
  38. 38.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  39. 39.Find the compound interest on ₹39000 at 20% per year for 3 years, compounded every year (in ₹).
  40. 40.A scooter is worth ₹6200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 59280
  2. 3192
  3. 68160
  4. 23540
  5. 3816
  6. 2164
  7. 3650
  8. 37908
  9. 20933
  10. 2525
  11. 1456
  12. 320
  13. 3550
  14. 63020
  15. 13932
  16. 260
  17. 36036
  18. 52000
  19. 17136
  20. 40032
  21. 377
  22. 11046
  23. 24334
  24. 11648
  25. 12167
  26. 35308
  27. 7566
  28. 44
  29. 47040
  30. 20250
  31. 13851
  32. 459
  33. 31311
  34. 740
  35. 144
  36. 585
  37. 1096
  38. 20577
  39. 28392
  40. 4960

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