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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 135 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹56500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  3. 3.Find the compound interest on ₹24200 at 10% per year for 2 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹4400 at 20% per year for 1 year, compounded every year (in ₹).
  5. 5.What amount will ₹12200 grow to in 1 year at 8% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹18400 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  11. 11.A scooter is worth ₹48800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  12. 12.Find the compound interest on ₹4400 at 15% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹4200 at 5% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹12000 at 20% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹44500 grow to in 3 years at 20% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹19300 at 20% per year for 2 years, compounded every year (in ₹).
  19. 19.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  20. 20.What amount will ₹49000 grow to in 3 years at 20% per year compound interest (in ₹)?
  21. 21.What amount will ₹7100 grow to in 1 year at 4% per year compound interest (in ₹)?
  22. 22.What amount will ₹8900 grow to in 1 year at 5% per year compound interest (in ₹)?
  23. 23.What amount will ₹47600 grow to in 2 years at 15% per year compound interest (in ₹)?
  24. 24.A town has 2500 people. The population grows by 4% every year. What will the population be after 2 years?
  25. 25.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  26. 26.A town has 7600 people. The population grows by 20% every year. What will the population be after 2 years?
  27. 27.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  28. 28.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
  29. 29.A town has 14800 people. The population grows by 12% every year. What will the population be after 1 year?
  30. 30.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
  31. 31.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
  32. 32.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?
  33. 33.A town has 23600 people. The population grows by 20% every year. What will the population be after 2 years?
  34. 34.What is the difference between the compound interest and the simple interest on ₹8800 at 25% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹54900 at 10% per year for 2 years (in ₹)?
  36. 36.What amount will ₹19000 grow to in 1 year at 8% per year compound interest (in ₹)?
  37. 37.What amount will ₹47600 grow to in 1 year at 10% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹22300 at 25% per year for 1 year, compounded every year (in ₹).
  39. 39.A scooter is worth ₹20000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  40. 40.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 58
  2. 28928
  3. 5082
  4. 880
  5. 13176
  6. 44225
  7. 10350
  8. 23328
  9. 6100
  10. 3783
  11. 35258
  12. 1419
  13. 210
  14. 112
  15. 8736
  16. 8325
  17. 76896
  18. 8492
  19. 41154
  20. 84672
  21. 7384
  22. 9345
  23. 62951
  24. 2704
  25. 8334
  26. 10944
  27. 96
  28. 15625
  29. 16576
  30. 62720
  31. 35152
  32. 41472
  33. 33984
  34. 550
  35. 549
  36. 20520
  37. 52360
  38. 5575
  39. 16928
  40. 25168

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