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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 145 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹4800 at 25% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹39400 at 4% per year for 1 year, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹4100 at 20% per year for 2 years (in ₹)?
  7. 7.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹28000 at 25% per year for 2 years (in ₹)?
  9. 9.A town has 36400 people. The population grows by 25% every year. What will the population be after 2 years?
  10. 10.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹40200 at 4% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹5400 at 12% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹48200 at 10% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹45500 at 20% per year for 3 years, compounded every year (in ₹).
  15. 15.What amount will ₹13100 grow to in 1 year at 12% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹5900 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.A scooter is worth ₹45600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  18. 18.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹11600 at 20% per year for 2 years (in ₹)?
  20. 20.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹24100 at 20% per year for 2 years (in ₹)?
  22. 22.A town has 12700 people. The population grows by 20% every year. What will the population be after 1 year?
  23. 23.What is the difference between the compound interest and the simple interest on ₹15500 at 10% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
  25. 25.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
  26. 26.What amount will ₹2000 grow to in 2 years at 15% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹14100 at 5% per year for 1 year, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹32400 at 25% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹22900 at 10% per year for 2 years (in ₹)?
  31. 31.What amount will ₹47500 grow to in 2 years at 4% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹17400 at 4% per year for 1 year, compounded every year (in ₹).
  33. 33.What amount will ₹36800 grow to in 2 years at 25% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
  35. 35.What amount will ₹36100 grow to in 1 year at 25% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹4800 at 12% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
  38. 38.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹23700 at 12% per year for 1 year, compounded every year (in ₹).
  40. 40.A town has 6000 people. The population grows by 15% every year. What will the population be after 2 years?

Answer key

  1. 208
  2. 300
  3. 1576
  4. 384
  5. 3475
  6. 164
  7. 55566
  8. 1750
  9. 56875
  10. 30
  11. 1608
  12. 648
  13. 482
  14. 33124
  15. 14672
  16. 590
  17. 41154
  18. 1261
  19. 464
  20. 64827
  21. 964
  22. 15240
  23. 155
  24. 684
  25. 14580
  26. 2645
  27. 705
  28. 12
  29. 8100
  30. 229
  31. 51376
  32. 696
  33. 57500
  34. 1224
  35. 45125
  36. 576
  37. 29
  38. 68992
  39. 2844
  40. 7935

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