Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 153 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹23000 grow to in 2 years at 10% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹42000 at 5% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹35800 at 20% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
6. 6.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹56400 grow to in 2 years at 5% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹32500 at 15% per year for 1 year, compounded every year (in ₹).
9. 9.A town has 6900 people. The population grows by 10% every year. What will the population be after 2 years?
10. 10.What is the difference between the compound interest and the simple interest on ₹8000 at 5% per year for 2 years (in ₹)?
11. 11.What amount will ₹38400 grow to in 1 year at 4% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
13. 13.A town has 46400 people. The population grows by 5% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹16300 at 20% per year for 2 years (in ₹)?
16. 16.A town has 2800 people. The population grows by 25% every year. What will the population be after 2 years?
17. 17.What amount will ₹54900 grow to in 1 year at 20% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
19. 19.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.A scooter is worth ₹24200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
21. 21.A town has 22000 people. The population grows by 25% every year. What will the population be after 2 years?
22. 22.A town has 41100 people. The population grows by 15% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹18200 at 20% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹5800 at 15% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
26. 26.What amount will ₹19400 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹28900 at 20% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹5200 grow to in 1 year at 20% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹8000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
31. 31.Find the compound interest on ₹24700 at 10% per year for 1 year, compounded every year (in ₹).
32. 32.A town has 18100 people. The population grows by 20% every year. What will the population be after 1 year?
33. 33.A town has 10500 people. The population grows by 8% every year. What will the population be after 1 year?
34. 34.A town has 54900 people. The population grows by 10% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹9200 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹57200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
37. 37.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹34700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
40. 40.A scooter is worth ₹52500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?

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