Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹58000 grow to in 1 year at 4% per year compound interest (in ₹)?
- 2.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
- 3.What amount will ₹50000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 4.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 5.A town has 54900 people. The population grows by 5% every year. What will the population be after 1 year?
- 6.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 7.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 8.What amount will ₹7500 grow to in 1 year at 15% per year compound interest (in ₹)?
- 9.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 10.What amount will ₹40300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 13.A scooter is worth ₹13900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 14.Find the compound interest on ₹12400 at 10% per year for 1 year, compounded every year (in ₹).
- 15.A town has 45700 people. The population grows by 8% every year. What will the population be after 1 year?
- 16.Find the compound interest on ₹42800 at 20% per year for 2 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹15900 at 20% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹49500 at 10% per year for 1 year, compounded every year (in ₹).
- 20.What amount will ₹55200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 21.A town has 16500 people. The population grows by 15% every year. What will the population be after 1 year?
- 22.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹27000 at 20% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
- 25.A scooter is worth ₹54200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹43000 at 20% per year for 3 years, compounded every year (in ₹).
- 28.A town has 45000 people. The population grows by 4% every year. What will the population be after 2 years?
- 29.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹39600 at 10% per year for 1 year, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹32400 at 5% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹21600 at 15% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
- 34.What amount will ₹13500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
- 37.A scooter is worth ₹30000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 38.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹39400 at 10% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹3000 at 5% per year for 1 year, compounded every year (in ₹).
Answer key
- 60320
- 67881
- 78125
- 28125
- 57645
- 96
- 17303
- 8625
- 4913
- 42315
- 6996
- 3783
- 12788
- 1240
- 49356
- 18832
- 720
- 636
- 4950
- 69000
- 18975
- 76
- 19656
- 2856
- 46070
- 160
- 31304
- 48672
- 28224
- 3960
- 81
- 486
- 387
- 14850
- 48
- 10675
- 25392
- 21350
- 8274
- 150
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