Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 155 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹39800 at 8% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹15200 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹36700 at 20% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹29800 at 10% per year for 2 years (in ₹)?
7. 7.A town has 22000 people. The population grows by 20% every year. What will the population be after 3 years?
8. 8.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹35600 at 25% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹17100 at 12% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹16200 at 10% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹8300 at 10% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹55400 at 8% per year for 1 year, compounded every year (in ₹).
15. 15.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
16. 16.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
17. 17.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
18. 18.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
19. 19.A town has 6100 people. The population grows by 5% every year. What will the population be after 1 year?
20. 20.Find the compound interest on ₹52500 at 20% per year for 3 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹39900 at 10% per year for 2 years (in ₹)?
22. 22.What amount will ₹59900 grow to in 1 year at 25% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹60000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
27. 27.A scooter is worth ₹23100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹50800 at 5% per year for 2 years (in ₹)?
29. 29.A town has 18600 people. The population grows by 15% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹49100 at 8% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹42600 grow to in 1 year at 8% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹57600 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹52200 at 8% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹39000 grow to in 3 years at 20% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹18800 at 12% per year for 1 year, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹46400 at 25% per year for 2 years (in ₹)?
40. 40.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?

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