Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 16 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹21900 at 10% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
4. 4.What amount will ₹23000 grow to in 1 year at 20% per year compound interest (in ₹)?
5. 5.What amount will ₹35200 grow to in 3 years at 25% per year compound interest (in ₹)?
6. 6.A town has 26200 people. The population grows by 25% every year. What will the population be after 1 year?
7. 7.What amount will ₹40000 grow to in 3 years at 10% per year compound interest (in ₹)?
8. 8.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
9. 9.Find the compound interest on ₹8000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.What amount will ₹15100 grow to in 1 year at 12% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹20500 at 4% per year for 1 year, compounded every year (in ₹).
12. 12.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
13. 13.What amount will ₹52600 grow to in 1 year at 15% per year compound interest (in ₹)?
14. 14.What amount will ₹6200 grow to in 1 year at 8% per year compound interest (in ₹)?
15. 15.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹50900 at 12% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹12700 grow to in 2 years at 10% per year compound interest (in ₹)?
19. 19.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
20. 20.A town has 22900 people. The population grows by 4% every year. What will the population be after 1 year?
21. 21.What amount will ₹44100 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹50400 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.A town has 19000 people. The population grows by 20% every year. What will the population be after 3 years?
25. 25.What is the difference between the compound interest and the simple interest on ₹4700 at 10% per year for 2 years (in ₹)?
26. 26.What amount will ₹44600 grow to in 1 year at 10% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹52000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹46400 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹58300 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹57400 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹10100 at 12% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹13000 at 10% per year for 3 years, compounded every year (in ₹).
35. 35.A scooter is worth ₹54400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹10000 at 20% per year for 3 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹9800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.A town has 37200 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?

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