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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 17 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹36800 at 25% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
  4. 4.What amount will ₹8400 grow to in 1 year at 5% per year compound interest (in ₹)?
  5. 5.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹18900 at 15% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹33900 at 15% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹53000 grow to in 3 years at 20% per year compound interest (in ₹)?
  10. 10.What amount will ₹41300 grow to in 1 year at 10% per year compound interest (in ₹)?
  11. 11.What amount will ₹57200 grow to in 1 year at 5% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹9000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  13. 13.Find the compound interest on ₹7800 at 10% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
  15. 15.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  16. 16.A town has 40400 people. The population grows by 15% every year. What will the population be after 2 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
  18. 18.What amount will ₹12400 grow to in 2 years at 15% per year compound interest (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹55000 at 10% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
  21. 21.A town has 11800 people. The population grows by 10% every year. What will the population be after 2 years?
  22. 22.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹55000 at 25% per year for 1 year, compounded every year (in ₹).
  25. 25.A scooter is worth ₹16000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  26. 26.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹8600 grow to in 2 years at 10% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  31. 31.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  32. 32.A scooter is worth ₹42300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  33. 33.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  34. 34.What amount will ₹27000 grow to in 3 years at 20% per year compound interest (in ₹)?
  35. 35.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  36. 36.Find the compound interest on ₹49700 at 12% per year for 1 year, compounded every year (in ₹).
  37. 37.A town has 18000 people. The population grows by 20% every year. What will the population be after 3 years?
  38. 38.A scooter is worth ₹30000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  39. 39.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹50400 at 25% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 2300
  2. 29478
  3. 49
  4. 8820
  5. 20577
  6. 108
  7. 2835
  8. 5085
  9. 91584
  10. 45430
  11. 60060
  12. 8550
  13. 780
  14. 71874
  15. 384
  16. 53429
  17. 810
  18. 16399
  19. 550
  20. 160
  21. 14278
  22. 4
  23. 8268
  24. 13750
  25. 11664
  26. 53750
  27. 3328
  28. 3640
  29. 10406
  30. 12501
  31. 12274
  32. 37224
  33. 4232
  34. 46656
  35. 31740
  36. 5964
  37. 31104
  38. 23232
  39. 8112
  40. 28350

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