Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹36800 at 25% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
- 4.What amount will ₹8400 grow to in 1 year at 5% per year compound interest (in ₹)?
- 5.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹18900 at 15% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹33900 at 15% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹53000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 10.What amount will ₹41300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 11.What amount will ₹57200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 12.A scooter is worth ₹9000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 13.Find the compound interest on ₹7800 at 10% per year for 1 year, compounded every year (in ₹).
- 14.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
- 15.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 16.A town has 40400 people. The population grows by 15% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹36000 at 15% per year for 2 years (in ₹)?
- 18.What amount will ₹12400 grow to in 2 years at 15% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹55000 at 10% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
- 21.A town has 11800 people. The population grows by 10% every year. What will the population be after 2 years?
- 22.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹55000 at 25% per year for 1 year, compounded every year (in ₹).
- 25.A scooter is worth ₹16000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 26.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
- 29.What amount will ₹8600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 31.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 32.A scooter is worth ₹42300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 33.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 34.What amount will ₹27000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 35.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 36.Find the compound interest on ₹49700 at 12% per year for 1 year, compounded every year (in ₹).
- 37.A town has 18000 people. The population grows by 20% every year. What will the population be after 3 years?
- 38.A scooter is worth ₹30000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 39.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹50400 at 25% per year for 2 years, compounded every year (in ₹).
Answer key
- 2300
- 29478
- 49
- 8820
- 20577
- 108
- 2835
- 5085
- 91584
- 45430
- 60060
- 8550
- 780
- 71874
- 384
- 53429
- 810
- 16399
- 550
- 160
- 14278
- 4
- 8268
- 13750
- 11664
- 53750
- 3328
- 3640
- 10406
- 12501
- 12274
- 37224
- 4232
- 46656
- 31740
- 5964
- 31104
- 23232
- 8112
- 28350
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