Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 162 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹17700 at 20% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹6000 at 25% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹8300 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
7. 7.What amount will ₹44900 grow to in 1 year at 12% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹33600 at 10% per year for 1 year, compounded every year (in ₹).
9. 9.A scooter is worth ₹47800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
10. 10.A town has 42400 people. The population grows by 20% every year. What will the population be after 2 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹54000 at 15% per year for 2 years (in ₹)?
13. 13.A town has 15000 people. The population grows by 20% every year. What will the population be after 3 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹3200 at 20% per year for 2 years (in ₹)?
15. 15.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
16. 16.What amount will ₹3200 grow to in 3 years at 25% per year compound interest (in ₹)?
17. 17.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
18. 18.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
19. 19.What amount will ₹20000 grow to in 1 year at 15% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹10200 at 20% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹53700 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹46300 grow to in 1 year at 10% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹40400 at 15% per year for 2 years (in ₹)?
24. 24.What amount will ₹54100 grow to in 1 year at 5% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
27. 27.A town has 44500 people. The population grows by 20% every year. What will the population be after 3 years?
28. 28.What amount will ₹47500 grow to in 2 years at 4% per year compound interest (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹54400 at 15% per year for 2 years (in ₹)?
30. 30.A town has 37200 people. The population grows by 20% every year. What will the population be after 1 year?
31. 31.What amount will ₹45400 grow to in 1 year at 15% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹44500 at 10% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹36200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
34. 34.What amount will ₹58200 grow to in 1 year at 4% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹27500 at 15% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 38400 people. The population grows by 4% every year. What will the population be after 1 year?
39. 39.A town has 27500 people. The population grows by 8% every year. What will the population be after 1 year?
40. 40.What is the difference between the compound interest and the simple interest on ₹44100 at 10% per year for 2 years (in ₹)?

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