Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 169 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹39200 at 25% per year for 2 years (in ₹)?
2. 2.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹22100 at 20% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹54400 grow to in 2 years at 5% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.A scooter is worth ₹56600. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
8. 8.A town has 7100 people. The population grows by 5% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹58500 at 4% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹36300 grow to in 2 years at 20% per year compound interest (in ₹)?
11. 11.A scooter is worth ₹9700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
12. 12.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
16. 16.What amount will ₹27200 grow to in 1 year at 4% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹9000 at 12% per year for 1 year, compounded every year (in ₹).
18. 18.A town has 46400 people. The population grows by 5% every year. What will the population be after 2 years?
19. 19.Find the compound interest on ₹21800 at 25% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
21. 21.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹38900 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.A scooter is worth ₹26400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
24. 24.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
26. 26.What amount will ₹17100 grow to in 1 year at 15% per year compound interest (in ₹)?
27. 27.What amount will ₹16300 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
29. 29.A scooter is worth ₹34600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
30. 30.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹31600 at 15% per year for 2 years (in ₹)?
33. 33.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹10000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
35. 35.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹28400 at 8% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
39. 39.What amount will ₹10800 grow to in 1 year at 10% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹11100 at 10% per year for 2 years, compounded every year (in ₹).

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