Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 170 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
2. 2.A town has 3000 people. The population grows by 10% every year. What will the population be after 3 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹58800 at 15% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹26200 at 15% per year for 1 year, compounded every year (in ₹).
5. 5.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
6. 6.Find the compound interest on ₹52000 at 4% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹48600 at 4% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
10. 10.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹50000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
17. 17.What amount will ₹19000 grow to in 1 year at 4% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹19700 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹18500 at 20% per year for 2 years (in ₹)?
21. 21.What amount will ₹54700 grow to in 1 year at 10% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹57000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
23. 23.Find the compound interest on ₹14400 at 15% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
25. 25.A town has 39000 people. The population grows by 15% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹38700 at 5% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
29. 29.A scooter is worth ₹17300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹35100 at 20% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹12800 at 15% per year for 2 years (in ₹)?
32. 32.A town has 28000 people. The population grows by 20% every year. What will the population be after 3 years?
33. 33.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
35. 35.A scooter is worth ₹16600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
36. 36.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
37. 37.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹19100 at 20% per year for 2 years (in ₹)?
40. 40.A town has 25800 people. The population grows by 20% every year. What will the population be after 1 year?

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