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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 18 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹36000 at 10% per year for 3 years, compounded every year (in ₹).
  4. 4.What amount will ₹38200 grow to in 1 year at 20% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹50300 at 20% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹52700 at 20% per year for 2 years (in ₹)?
  7. 7.A scooter is worth ₹2900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹45800 at 10% per year for 2 years (in ₹)?
  9. 9.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
  10. 10.Find the compound interest on ₹54100 at 25% per year for 1 year, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹39600 at 8% per year for 1 year, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  14. 14.A town has 26200 people. The population grows by 20% every year. What will the population be after 1 year?
  15. 15.What is the difference between the compound interest and the simple interest on ₹36200 at 20% per year for 2 years (in ₹)?
  16. 16.A town has 14300 people. The population grows by 10% every year. What will the population be after 2 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  18. 18.What amount will ₹8500 grow to in 1 year at 8% per year compound interest (in ₹)?
  19. 19.A town has 23200 people. The population grows by 15% every year. What will the population be after 2 years?
  20. 20.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  21. 21.A town has 27700 people. The population grows by 5% every year. What will the population be after 1 year?
  22. 22.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
  25. 25.A town has 54000 people. The population grows by 15% every year. What will the population be after 2 years?
  26. 26.What is the difference between the compound interest and the simple interest on ₹6000 at 15% per year for 2 years (in ₹)?
  27. 27.A town has 12800 people. The population grows by 5% every year. What will the population be after 2 years?
  28. 28.Find the compound interest on ₹21200 at 5% per year for 1 year, compounded every year (in ₹).
  29. 29.A town has 15200 people. The population grows by 5% every year. What will the population be after 2 years?
  30. 30.A scooter is worth ₹19100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  31. 31.What amount will ₹2400 grow to in 2 years at 5% per year compound interest (in ₹)?
  32. 32.What amount will ₹4400 grow to in 1 year at 20% per year compound interest (in ₹)?
  33. 33.A scooter is worth ₹42400. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹19200 at 5% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹55200 at 15% per year for 1 year, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹24800 at 5% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹42400 at 10% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹5500 at 10% per year for 2 years (in ₹)?

Answer key

  1. 324
  2. 1250
  3. 11916
  4. 45840
  5. 2012
  6. 2108
  7. 2610
  8. 458
  9. 75264
  10. 13525
  11. 1150
  12. 3168
  13. 128
  14. 31440
  15. 1448
  16. 17303
  17. 192
  18. 9180
  19. 30682
  20. 216
  21. 29085
  22. 3310
  23. 900
  24. 35075
  25. 71415
  26. 135
  27. 14112
  28. 1060
  29. 16758
  30. 15471
  31. 2646
  32. 5280
  33. 37312
  34. 48
  35. 105
  36. 8334
  37. 8280
  38. 1240
  39. 424
  40. 55

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