Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 2.A town has 34100 people. The population grows by 15% every year. What will the population be after 1 year?
- 3.Find the compound interest on ₹19000 at 20% per year for 3 years, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹14600 at 10% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹51100 at 10% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
- 7.What amount will ₹3700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹10100 at 20% per year for 2 years, compounded every year (in ₹).
- 9.A town has 21400 people. The population grows by 4% every year. What will the population be after 1 year?
- 10.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
- 11.A town has 27200 people. The population grows by 15% every year. What will the population be after 2 years?
- 12.Find the compound interest on ₹51500 at 20% per year for 3 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹30400 at 15% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 15.A town has 15400 people. The population grows by 8% every year. What will the population be after 1 year?
- 16.A scooter is worth ₹13500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 17.What amount will ₹26400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹55500 at 20% per year for 3 years, compounded every year (in ₹).
- 19.A town has 2300 people. The population grows by 20% every year. What will the population be after 1 year?
- 20.A town has 16000 people. The population grows by 15% every year. What will the population be after 1 year?
- 21.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 22.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹12900 at 8% per year for 1 year, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹15500 at 10% per year for 2 years (in ₹)?
- 25.What amount will ₹38400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹40800 at 25% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹32300 at 20% per year for 2 years, compounded every year (in ₹).
- 29.What amount will ₹42100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹52000 at 5% per year for 2 years, compounded every year (in ₹).
- 32.A town has 6400 people. The population grows by 25% every year. What will the population be after 3 years?
- 33.What amount will ₹24900 grow to in 1 year at 12% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹50400 at 10% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹58800 at 10% per year for 2 years, compounded every year (in ₹).
- 36.What amount will ₹10200 grow to in 1 year at 15% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹58400 at 12% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹41600 at 25% per year for 2 years (in ₹)?
- 40.What amount will ₹53300 grow to in 1 year at 15% per year compound interest (in ₹)?
Answer key
- 144
- 39215
- 13832
- 146
- 511
- 1428
- 4440
- 4444
- 22256
- 49
- 35972
- 37492
- 4560
- 24
- 16632
- 11475
- 29568
- 40404
- 2760
- 18400
- 16606
- 24334
- 1032
- 155
- 75000
- 765
- 2550
- 14212
- 50941
- 28
- 5330
- 12500
- 27888
- 504
- 12348
- 11730
- 7008
- 51850
- 2600
- 61295
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