Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 172 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
2. 2.What amount will ₹18000 grow to in 1 year at 10% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹50400 at 25% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹31200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
5. 5.A town has 8800 people. The population grows by 8% every year. What will the population be after 1 year?
6. 6.Find the compound interest on ₹41500 at 20% per year for 1 year, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
8. 8.A town has 33000 people. The population grows by 20% every year. What will the population be after 2 years?
9. 9.What amount will ₹49400 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 50200 people. The population grows by 10% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹56800 at 10% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
15. 15.A scooter is worth ₹34400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
16. 16.A scooter is worth ₹30400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
18. 18.A town has 44300 people. The population grows by 20% every year. What will the population be after 2 years?
19. 19.A scooter is worth ₹52000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
20. 20.Find the compound interest on ₹32100 at 4% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹20600 at 8% per year for 1 year, compounded every year (in ₹).
24. 24.A town has 8000 people. The population grows by 25% every year. What will the population be after 3 years?
25. 25.A town has 25000 people. The population grows by 4% every year. What will the population be after 2 years?
26. 26.A scooter is worth ₹40600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
27. 27.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
28. 28.A town has 39000 people. The population grows by 20% every year. What will the population be after 3 years?
29. 29.A scooter is worth ₹49400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
31. 31.What amount will ₹35000 grow to in 1 year at 8% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹60000 at 25% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 59600 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).

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