Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 177 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹36300 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹16400 at 10% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹42500 grow to in 2 years at 4% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
6. 6.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹15000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
9. 9.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
10. 10.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
11. 11.A town has 6100 people. The population grows by 10% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹57200 at 15% per year for 2 years (in ₹)?
13. 13.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
14. 14.What amount will ₹44500 grow to in 1 year at 25% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹20400 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹18400 at 10% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹51800 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹19000 at 8% per year for 1 year, compounded every year (in ₹).
19. 19.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹37800 at 5% per year for 1 year, compounded every year (in ₹).
22. 22.A scooter is worth ₹13700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
23. 23.What amount will ₹43300 grow to in 1 year at 5% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹5300 at 25% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
27. 27.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
28. 28.A scooter is worth ₹54000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
29. 29.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
30. 30.A town has 47300 people. The population grows by 10% every year. What will the population be after 1 year?
31. 31.What amount will ₹26400 grow to in 1 year at 25% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹29300 at 20% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
34. 34.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹33100 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹20000 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹3000 at 10% per year for 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹53600 at 10% per year for 1 year, compounded every year (in ₹).
40. 40.A scooter is worth ₹49500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?

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