Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 182 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹49600 at 5% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹44500 at 20% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹45900 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
6. 6.A town has 55000 people. The population grows by 20% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹7600 at 15% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
9. 9.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
10. 10.A town has 40100 people. The population grows by 5% every year. What will the population be after 1 year?
11. 11.Find the compound interest on ₹34500 at 10% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹41200 grow to in 2 years at 15% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹17700 at 15% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹30400 at 25% per year for 2 years, compounded every year (in ₹).
15. 15.A town has 4800 people. The population grows by 25% every year. What will the population be after 1 year?
16. 16.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
17. 17.A town has 56600 people. The population grows by 4% every year. What will the population be after 1 year?
18. 18.A town has 59200 people. The population grows by 25% every year. What will the population be after 3 years?
19. 19.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹28900 at 20% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹60000 at 8% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
25. 25.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
26. 26.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
27. 27.What amount will ₹10800 grow to in 1 year at 25% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹57500 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹47600 at 8% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹20600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
33. 33.A scooter is worth ₹36400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹31600 at 12% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹51000 grow to in 1 year at 10% per year compound interest (in ₹)?
37. 37.What amount will ₹33000 grow to in 3 years at 20% per year compound interest (in ₹)?
38. 38.What amount will ₹40000 grow to in 2 years at 4% per year compound interest (in ₹)?
39. 39.What amount will ₹31600 grow to in 1 year at 12% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹13600 at 25% per year for 2 years, compounded every year (in ₹).

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