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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 183 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹28400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  2. 2.What amount will ₹25600 grow to in 1 year at 15% per year compound interest (in ₹)?
  3. 3.What amount will ₹30500 grow to in 1 year at 8% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹28600 at 20% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹50000 at 10% per year for 3 years, compounded every year (in ₹).
  9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
  11. 11.What amount will ₹20500 grow to in 1 year at 5% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹40000 at 4% per year for 1 year, compounded every year (in ₹).
  14. 14.What amount will ₹33200 grow to in 2 years at 15% per year compound interest (in ₹)?
  15. 15.A town has 54400 people. The population grows by 4% every year. What will the population be after 1 year?
  16. 16.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  17. 17.A town has 17400 people. The population grows by 12% every year. What will the population be after 1 year?
  18. 18.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹33200 at 25% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹26800 at 5% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  28. 28.A scooter is worth ₹11100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  29. 29.Find the compound interest on ₹6800 at 5% per year for 2 years, compounded every year (in ₹).
  30. 30.A scooter is worth ₹46400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  31. 31.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
  32. 32.A scooter is worth ₹52800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What amount will ₹19100 grow to in 1 year at 15% per year compound interest (in ₹)?
  34. 34.A town has 46600 people. The population grows by 8% every year. What will the population be after 1 year?
  35. 35.What amount will ₹12600 grow to in 1 year at 10% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹46700 at 15% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹37200 at 5% per year for 2 years (in ₹)?
  38. 38.What amount will ₹13600 grow to in 2 years at 5% per year compound interest (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹49200 at 5% per year for 2 years (in ₹)?
  40. 40.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?

Answer key

  1. 25631
  2. 29440
  3. 32940
  4. 3972
  5. 4488
  6. 12501
  7. 1144
  8. 16550
  9. 9261
  10. 29
  11. 21525
  12. 368
  13. 1600
  14. 43907
  15. 56576
  16. 96
  17. 19488
  18. 9720
  19. 52
  20. 2075
  21. 4
  22. 320
  23. 2747
  24. 414
  25. 1800
  26. 2522
  27. 180
  28. 8880
  29. 697
  30. 29696
  31. 15972
  32. 47652
  33. 21965
  34. 50328
  35. 13860
  36. 7005
  37. 93
  38. 14994
  39. 123
  40. 18750

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