Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 186 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
2. 2.What amount will ₹21200 grow to in 1 year at 8% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹54500 at 20% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹52400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
5. 5.What amount will ₹27400 grow to in 2 years at 10% per year compound interest (in ₹)?
6. 6.A town has 14000 people. The population grows by 10% every year. What will the population be after 3 years?
7. 7.Find the compound interest on ₹56000 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹12000 at 20% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹59600 at 5% per year for 2 years, compounded every year (in ₹).
10. 10.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹36200 at 15% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹43100 at 20% per year for 2 years (in ₹)?
13. 13.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹43900 at 12% per year for 1 year, compounded every year (in ₹).
15. 15.A scooter is worth ₹15800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
17. 17.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹2000 at 5% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹39700 grow to in 1 year at 8% per year compound interest (in ₹)?
21. 21.What amount will ₹33100 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
23. 23.A town has 15200 people. The population grows by 5% every year. What will the population be after 2 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹20200. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
26. 26.What amount will ₹36800 grow to in 2 years at 5% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
28. 28.A scooter is worth ₹25300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹49900 at 20% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹47700 at 20% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹36900 at 10% per year for 2 years (in ₹)?
34. 34.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
35. 35.A scooter is worth ₹14200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
36. 36.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
38. 38.A town has 40400 people. The population grows by 15% every year. What will the population be after 2 years?
39. 39.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹54900 at 10% per year for 2 years, compounded every year (in ₹).

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