Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 191 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 6000 people. The population grows by 25% every year. What will the population be after 1 year?
2. 2.What is the difference between the compound interest and the simple interest on ₹17500 at 20% per year for 2 years (in ₹)?
3. 3.A town has 46600 people. The population grows by 25% every year. What will the population be after 1 year?
4. 4.What is the difference between the compound interest and the simple interest on ₹44700 at 20% per year for 2 years (in ₹)?
5. 5.A town has 16000 people. The population grows by 25% every year. What will the population be after 3 years?
6. 6.A town has 58600 people. The population grows by 12% every year. What will the population be after 1 year?
7. 7.What is the difference between the compound interest and the simple interest on ₹4800 at 15% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹38300 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 44000 people. The population grows by 10% every year. What will the population be after 3 years?
11. 11.A town has 48400 people. The population grows by 5% every year. What will the population be after 2 years?
12. 12.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
13. 13.A scooter is worth ₹10400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
14. 14.Find the compound interest on ₹50000 at 5% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹4800 at 25% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹5100 at 4% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹54500 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.What amount will ₹28100 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.What amount will ₹2000 grow to in 2 years at 15% per year compound interest (in ₹)?
21. 21.A town has 42500 people. The population grows by 20% every year. What will the population be after 3 years?
22. 22.What amount will ₹10200 grow to in 2 years at 20% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹28900 at 20% per year for 2 years (in ₹)?
24. 24.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
25. 25.What amount will ₹12800 grow to in 3 years at 25% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
28. 28.What amount will ₹3800 grow to in 1 year at 15% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹10000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
30. 30.A scooter is worth ₹58500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹11700 at 20% per year for 2 years (in ₹)?
32. 32.What amount will ₹3600 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹47900 at 20% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹28400 at 25% per year for 2 years (in ₹)?
35. 35.A town has 55200 people. The population grows by 5% every year. What will the population be after 2 years?
36. 36.A scooter is worth ₹35700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
37. 37.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹2800 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹54800 at 8% per year for 1 year, compounded every year (in ₹).

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