Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 196 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹16600 grow to in 1 year at 4% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹56800 at 25% per year for 2 years (in ₹)?
3. 3.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹32500 at 20% per year for 2 years (in ₹)?
5. 5.What amount will ₹27200 grow to in 1 year at 8% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹7900 at 20% per year for 1 year, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹20500 at 20% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹39300 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹48900 grow to in 1 year at 8% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹28000 at 15% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹55200 grow to in 1 year at 20% per year compound interest (in ₹)?
15. 15.A town has 16000 people. The population grows by 25% every year. What will the population be after 2 years?
16. 16.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹19000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
22. 22.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
23. 23.What amount will ₹57900 grow to in 1 year at 20% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹56700 at 15% per year for 1 year, compounded every year (in ₹).
25. 25.A town has 48500 people. The population grows by 20% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
27. 27.A town has 59200 people. The population grows by 15% every year. What will the population be after 2 years?
28. 28.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
29. 29.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹22000 at 5% per year for 2 years, compounded every year (in ₹).
32. 32.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.A town has 48300 people. The population grows by 5% every year. What will the population be after 1 year?
34. 34.What amount will ₹18800 grow to in 2 years at 5% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹46000 at 15% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹35200 at 25% per year for 2 years (in ₹)?
38. 38.What amount will ₹15800 grow to in 1 year at 20% per year compound interest (in ₹)?
39. 39.What amount will ₹33700 grow to in 1 year at 10% per year compound interest (in ₹)?
40. 40.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?

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