← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 197 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A town has 58400 people. The population grows by 5% every year. What will the population be after 2 years?
  2. 2.What amount will ₹3700 grow to in 1 year at 12% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹46400 at 15% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹32300 at 25% per year for 1 year, compounded every year (in ₹).
  5. 5.A town has 40800 people. The population grows by 20% every year. What will the population be after 2 years?
  6. 6.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  7. 7.What amount will ₹31600 grow to in 2 years at 5% per year compound interest (in ₹)?
  8. 8.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  9. 9.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹2600 grow to in 1 year at 10% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹29800 at 10% per year for 1 year, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹47200 at 5% per year for 2 years, compounded every year (in ₹).
  14. 14.A scooter is worth ₹56400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  15. 15.What amount will ₹31200 grow to in 2 years at 25% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  17. 17.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹17300 at 8% per year for 1 year, compounded every year (in ₹).
  19. 19.A scooter is worth ₹6300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹19000 at 10% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
  22. 22.What amount will ₹49700 grow to in 1 year at 12% per year compound interest (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹15600 at 15% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  26. 26.What amount will ₹45600 grow to in 2 years at 5% per year compound interest (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
  29. 29.What amount will ₹38600 grow to in 2 years at 20% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  31. 31.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  32. 32.What amount will ₹19100 grow to in 1 year at 5% per year compound interest (in ₹)?
  33. 33.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
  34. 34.What is the difference between the compound interest and the simple interest on ₹54200 at 10% per year for 2 years (in ₹)?
  35. 35.A town has 43000 people. The population grows by 10% every year. What will the population be after 3 years?
  36. 36.Find the compound interest on ₹22700 at 5% per year for 1 year, compounded every year (in ₹).
  37. 37.What amount will ₹43700 grow to in 1 year at 5% per year compound interest (in ₹)?
  38. 38.A town has 10400 people. The population grows by 5% every year. What will the population be after 2 years?
  39. 39.Find the compound interest on ₹9800 at 15% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?

Answer key

  1. 64386
  2. 4144
  3. 6960
  4. 8075
  5. 58752
  6. 176
  7. 34839
  8. 8464
  9. 1248
  10. 2860
  11. 612
  12. 2980
  13. 4838
  14. 40749
  15. 48750
  16. 5044
  17. 10648
  18. 1384
  19. 5355
  20. 190
  21. 64
  22. 55664
  23. 351
  24. 11
  25. 828
  26. 50274
  27. 72
  28. 148
  29. 55584
  30. 4
  31. 27436
  32. 20055
  33. 8112
  34. 542
  35. 57233
  36. 1135
  37. 45885
  38. 11466
  39. 1470
  40. 31250

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets