Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹17700 at 15% per year for 1 year, compounded every year (in ₹).
- 3.Find the compound interest on ₹14400 at 5% per year for 2 years, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹11200 at 5% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹21600 at 15% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
- 9.A scooter is worth ₹42200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 10.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 11.What is the difference between the compound interest and the simple interest on ₹24300 at 20% per year for 2 years (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹16800 at 25% per year for 2 years (in ₹)?
- 13.A scooter is worth ₹7600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 14.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹53700 at 5% per year for 1 year, compounded every year (in ₹).
- 16.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 17.What amount will ₹31000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹18700 at 25% per year for 1 year, compounded every year (in ₹).
- 20.Find the compound interest on ₹7600 at 10% per year for 2 years, compounded every year (in ₹).
- 21.What amount will ₹32000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹7600 at 5% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 24.A town has 12800 people. The population grows by 25% every year. What will the population be after 2 years?
- 25.What amount will ₹9300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
- 27.A town has 43600 people. The population grows by 15% every year. What will the population be after 2 years?
- 28.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
- 29.A scooter is worth ₹50700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 31.A scooter is worth ₹53800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 32.A town has 60000 people. The population grows by 8% every year. What will the population be after 2 years?
- 33.What is the difference between the compound interest and the simple interest on ₹47200 at 15% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 35.A scooter is worth ₹10600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹26900 at 20% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹13000 at 10% per year for 3 years, compounded every year (in ₹).
- 38.A scooter is worth ₹37300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹6000 at 5% per year for 2 years (in ₹)?
- 40.A scooter is worth ₹38400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
Answer key
- 48668
- 2655
- 1476
- 20
- 28
- 6305
- 486
- 45750
- 37980
- 46305
- 972
- 1050
- 7220
- 19825
- 2685
- 29744
- 35650
- 17
- 4675
- 1596
- 62500
- 19
- 51850
- 20000
- 10230
- 9150
- 57661
- 16
- 44616
- 48
- 49496
- 69984
- 1062
- 41154
- 6784
- 1076
- 4303
- 27975
- 15
- 34656
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