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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 205 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 45000 people. The population grows by 20% every year. What will the population be after 3 years?
  2. 2.A town has 40800 people. The population grows by 15% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹35700 at 20% per year for 2 years (in ₹)?
  4. 4.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹54900 at 15% per year for 1 year, compounded every year (in ₹).
  6. 6.What amount will ₹47200 grow to in 1 year at 8% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹11000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  8. 8.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
  9. 9.What amount will ₹20500 grow to in 3 years at 20% per year compound interest (in ₹)?
  10. 10.A town has 48800 people. The population grows by 10% every year. What will the population be after 2 years?
  11. 11.A town has 16600 people. The population grows by 10% every year. What will the population be after 1 year?
  12. 12.What amount will ₹52400 grow to in 1 year at 5% per year compound interest (in ₹)?
  13. 13.What amount will ₹3700 grow to in 2 years at 20% per year compound interest (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹27400 at 20% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹57600 at 25% per year for 2 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹16400 at 15% per year for 2 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹44500 at 12% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹7200 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.A town has 16000 people. The population grows by 4% every year. What will the population be after 1 year?
  21. 21.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
  23. 23.A town has 40000 people. The population grows by 10% every year. What will the population be after 3 years?
  24. 24.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹31000 at 10% per year for 2 years (in ₹)?
  27. 27.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  28. 28.A scooter is worth ₹47500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹2600 at 4% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹30800 grow to in 2 years at 25% per year compound interest (in ₹)?
  32. 32.A town has 44800 people. The population grows by 25% every year. What will the population be after 2 years?
  33. 33.What amount will ₹53400 grow to in 1 year at 20% per year compound interest (in ₹)?
  34. 34.What amount will ₹14300 grow to in 2 years at 20% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹39500 at 5% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹14400 grow to in 2 years at 20% per year compound interest (in ₹)?
  37. 37.What amount will ₹6500 grow to in 3 years at 20% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹17400 at 20% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹3000 at 20% per year for 1 year, compounded every year (in ₹).
  40. 40.A scooter is worth ₹33100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 77760
  2. 46920
  3. 1428
  4. 100000
  5. 8235
  6. 50976
  7. 5632
  8. 69984
  9. 35424
  10. 59048
  11. 18260
  12. 55020
  13. 5328
  14. 101
  15. 1096
  16. 32400
  17. 5289
  18. 5340
  19. 1512
  20. 16640
  21. 1836
  22. 133
  23. 53240
  24. 130
  25. 4992
  26. 310
  27. 46305
  28. 36784
  29. 216
  30. 104
  31. 48125
  32. 70000
  33. 64080
  34. 20592
  35. 1975
  36. 20736
  37. 11232
  38. 696
  39. 600
  40. 26811

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