Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹20600 at 4% per year for 1 year, compounded every year (in ₹).
- 2.What amount will ₹60000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 3.What amount will ₹9200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹44300 at 20% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹59200 at 10% per year for 1 year, compounded every year (in ₹).
- 6.A town has 42600 people. The population grows by 20% every year. What will the population be after 1 year?
- 7.What amount will ₹39000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹35900 at 8% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 10.What amount will ₹18800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 12.A scooter is worth ₹25000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹58800 at 5% per year for 2 years (in ₹)?
- 14.What amount will ₹59600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 15.What amount will ₹23400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹54000 at 20% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹36500 at 10% per year for 1 year, compounded every year (in ₹).
- 18.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹28300 at 10% per year for 1 year, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
- 22.A town has 43100 people. The population grows by 4% every year. What will the population be after 1 year?
- 23.Find the compound interest on ₹58800 at 5% per year for 1 year, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.A town has 60000 people. The population grows by 20% every year. What will the population be after 2 years?
- 27.What amount will ₹15200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 28.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
- 30.A town has 43700 people. The population grows by 25% every year. What will the population be after 1 year?
- 31.Find the compound interest on ₹31000 at 25% per year for 1 year, compounded every year (in ₹).
- 32.Find the compound interest on ₹6300 at 10% per year for 1 year, compounded every year (in ₹).
- 33.What amount will ₹6000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 34.What amount will ₹59400 grow to in 1 year at 10% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹6400 at 10% per year for 1 year, compounded every year (in ₹).
- 36.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 37.A scooter is worth ₹32300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
- 39.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
- 40.A town has 43300 people. The population grows by 20% every year. What will the population be after 1 year?
Answer key
- 824
- 79350
- 10120
- 8860
- 5920
- 51120
- 56160
- 2872
- 73002
- 20680
- 8
- 18225
- 147
- 93125
- 33696
- 2160
- 3650
- 51909
- 1071
- 2830
- 108
- 44824
- 2940
- 612
- 5044
- 86400
- 20102
- 34496
- 30500
- 54625
- 7750
- 630
- 10368
- 65340
- 640
- 27783
- 27455
- 40
- 34496
- 51960
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