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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 217 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.What amount will ₹15300 grow to in 2 years at 10% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹39800 at 8% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
  5. 5.A town has 11400 people. The population grows by 10% every year. What will the population be after 1 year?
  6. 6.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  7. 7.A town has 18000 people. The population grows by 10% every year. What will the population be after 3 years?
  8. 8.Find the compound interest on ₹47200 at 15% per year for 2 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹50000 at 10% per year for 2 years (in ₹)?
  10. 10.A scooter is worth ₹42500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  11. 11.Find the compound interest on ₹38000 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.A town has 50200 people. The population grows by 10% every year. What will the population be after 2 years?
  13. 13.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹20900 at 20% per year for 2 years, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹15700 at 5% per year for 1 year, compounded every year (in ₹).
  16. 16.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹55900 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹21400 at 10% per year for 1 year, compounded every year (in ₹).
  20. 20.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
  22. 22.A town has 8300 people. The population grows by 8% every year. What will the population be after 1 year?
  23. 23.A scooter is worth ₹26800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  24. 24.What amount will ₹52800 grow to in 2 years at 20% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹31600 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  29. 29.What amount will ₹41300 grow to in 1 year at 15% per year compound interest (in ₹)?
  30. 30.A town has 17300 people. The population grows by 5% every year. What will the population be after 1 year?
  31. 31.Find the compound interest on ₹48100 at 20% per year for 1 year, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹41400 at 20% per year for 2 years (in ₹)?
  33. 33.A town has 6500 people. The population grows by 20% every year. What will the population be after 1 year?
  34. 34.A town has 27200 people. The population grows by 10% every year. What will the population be after 2 years?
  35. 35.Find the compound interest on ₹3300 at 5% per year for 1 year, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  37. 37.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
  39. 39.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  40. 40.A town has 47600 people. The population grows by 10% every year. What will the population be after 2 years?

Answer key

  1. 18513
  2. 67
  3. 3184
  4. 1020
  5. 12540
  6. 12167
  7. 23958
  8. 15222
  9. 500
  10. 32912
  11. 3800
  12. 60742
  13. 68992
  14. 9196
  15. 785
  16. 16128
  17. 43904
  18. 5590
  19. 2140
  20. 4761
  21. 136
  22. 8964
  23. 24120
  24. 76032
  25. 4965
  26. 6636
  27. 34295
  28. 288
  29. 47495
  30. 18165
  31. 9620
  32. 1656
  33. 7800
  34. 32912
  35. 165
  36. 5044
  37. 49572
  38. 32
  39. 27436
  40. 57596

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