Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹15300 grow to in 2 years at 10% per year compound interest (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹39800 at 8% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
- 5.A town has 11400 people. The population grows by 10% every year. What will the population be after 1 year?
- 6.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 7.A town has 18000 people. The population grows by 10% every year. What will the population be after 3 years?
- 8.Find the compound interest on ₹47200 at 15% per year for 2 years, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹50000 at 10% per year for 2 years (in ₹)?
- 10.A scooter is worth ₹42500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 11.Find the compound interest on ₹38000 at 10% per year for 1 year, compounded every year (in ₹).
- 12.A town has 50200 people. The population grows by 10% every year. What will the population be after 2 years?
- 13.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹20900 at 20% per year for 2 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹15700 at 5% per year for 1 year, compounded every year (in ₹).
- 16.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 17.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹55900 at 10% per year for 1 year, compounded every year (in ₹).
- 19.Find the compound interest on ₹21400 at 10% per year for 1 year, compounded every year (in ₹).
- 20.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
- 22.A town has 8300 people. The population grows by 8% every year. What will the population be after 1 year?
- 23.A scooter is worth ₹26800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 24.What amount will ₹52800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 25.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹31600 at 10% per year for 2 years, compounded every year (in ₹).
- 27.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 29.What amount will ₹41300 grow to in 1 year at 15% per year compound interest (in ₹)?
- 30.A town has 17300 people. The population grows by 5% every year. What will the population be after 1 year?
- 31.Find the compound interest on ₹48100 at 20% per year for 1 year, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹41400 at 20% per year for 2 years (in ₹)?
- 33.A town has 6500 people. The population grows by 20% every year. What will the population be after 1 year?
- 34.A town has 27200 people. The population grows by 10% every year. What will the population be after 2 years?
- 35.Find the compound interest on ₹3300 at 5% per year for 1 year, compounded every year (in ₹).
- 36.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
- 39.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 40.A town has 47600 people. The population grows by 10% every year. What will the population be after 2 years?
Answer key
- 18513
- 67
- 3184
- 1020
- 12540
- 12167
- 23958
- 15222
- 500
- 32912
- 3800
- 60742
- 68992
- 9196
- 785
- 16128
- 43904
- 5590
- 2140
- 4761
- 136
- 8964
- 24120
- 76032
- 4965
- 6636
- 34295
- 288
- 47495
- 18165
- 9620
- 1656
- 7800
- 32912
- 165
- 5044
- 49572
- 32
- 27436
- 57596
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