Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 218 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹10300 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹16800 at 15% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
4. 4.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
5. 5.Find the compound interest on ₹46800 at 20% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹40200 grow to in 2 years at 20% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹18700 at 10% per year for 2 years (in ₹)?
8. 8.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹41100 at 10% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹27100 at 10% per year for 2 years (in ₹)?
13. 13.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
14. 14.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
17. 17.A town has 40600 people. The population grows by 12% every year. What will the population be after 1 year?
18. 18.Find the compound interest on ₹19800 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹46400 at 25% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹58800 at 10% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹16400 at 25% per year for 2 years, compounded every year (in ₹).
23. 23.What amount will ₹7900 grow to in 1 year at 20% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹50300 at 12% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹44400 grow to in 1 year at 12% per year compound interest (in ₹)?
26. 26.A town has 47400 people. The population grows by 25% every year. What will the population be after 1 year?
27. 27.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹49700 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹39600 at 15% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
32. 32.What amount will ₹37500 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
34. 34.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹19200 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
37. 37.What amount will ₹55600 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.A town has 9500 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹5200 at 25% per year for 2 years, compounded every year (in ₹).

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