← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 222 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹31100 at 20% per year for 2 years (in ₹)?
  3. 3.A scooter is worth ₹6800. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹5200 at 4% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹6400 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.What amount will ₹8200 grow to in 1 year at 5% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
  10. 10.A town has 47100 people. The population grows by 4% every year. What will the population be after 1 year?
  11. 11.A town has 41400 people. The population grows by 10% every year. What will the population be after 2 years?
  12. 12.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹14400 at 25% per year for 2 years (in ₹)?
  14. 14.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
  15. 15.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹45200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹24700 at 10% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹55900 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  20. 20.A town has 26200 people. The population grows by 4% every year. What will the population be after 1 year?
  21. 21.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹45600 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹46400 at 10% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹2000 at 5% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
  26. 26.What amount will ₹50400 grow to in 1 year at 10% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹12900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  28. 28.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
  29. 29.What amount will ₹10300 grow to in 1 year at 8% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹54500 at 20% per year for 3 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹57500 at 20% per year for 3 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹5800 at 5% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹31600 grow to in 2 years at 20% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹5500 at 20% per year for 3 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹18400 at 25% per year for 2 years, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹36400 at 15% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹56800 at 25% per year for 2 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹42900 at 20% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?

Answer key

  1. 144
  2. 1244
  3. 6528
  4. 28
  5. 4167
  6. 208
  7. 3600
  8. 8610
  9. 500
  10. 48984
  11. 50094
  12. 18816
  13. 900
  14. 56448
  15. 90625
  16. 40793
  17. 247
  18. 11739
  19. 192
  20. 27248
  21. 612
  22. 4560
  23. 464
  24. 5
  25. 1325
  26. 55440
  27. 10320
  28. 2652
  29. 11124
  30. 39676
  31. 1986
  32. 41860
  33. 290
  34. 45504
  35. 4004
  36. 10350
  37. 819
  38. 31950
  39. 1716
  40. 80

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets