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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 225 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹46100 grow to in 1 year at 20% per year compound interest (in ₹)?
  2. 2.What amount will ₹25400 grow to in 2 years at 10% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹16600 at 10% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹19000 at 10% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  6. 6.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹8300 at 10% per year for 2 years (in ₹)?
  8. 8.A town has 2600 people. The population grows by 5% every year. What will the population be after 1 year?
  9. 9.A town has 5600 people. The population grows by 15% every year. What will the population be after 1 year?
  10. 10.Find the compound interest on ₹44400 at 15% per year for 2 years, compounded every year (in ₹).
  11. 11.A scooter is worth ₹40800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  12. 12.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  13. 13.What amount will ₹38900 grow to in 2 years at 20% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹43500 at 10% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹6500 at 10% per year for 2 years (in ₹)?
  16. 16.What amount will ₹50000 grow to in 3 years at 10% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹11500 at 20% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  22. 22.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
  23. 23.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  25. 25.A scooter is worth ₹40600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  26. 26.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
  27. 27.What amount will ₹59600 grow to in 2 years at 5% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹39900 at 25% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹46000 at 20% per year for 3 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹42300 at 20% per year for 2 years, compounded every year (in ₹).
  31. 31.A scooter is worth ₹12400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  32. 32.A scooter is worth ₹10000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  33. 33.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  35. 35.A town has 57500 people. The population grows by 4% every year. What will the population be after 2 years?
  36. 36.What amount will ₹34400 grow to in 2 years at 5% per year compound interest (in ₹)?
  37. 37.What amount will ₹58000 grow to in 1 year at 25% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
  40. 40.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?

Answer key

  1. 55320
  2. 30734
  3. 3486
  4. 190
  5. 384
  6. 55566
  7. 83
  8. 2730
  9. 6440
  10. 14319
  11. 32640
  12. 100000
  13. 56016
  14. 4350
  15. 65
  16. 66550
  17. 5060
  18. 1325
  19. 9152
  20. 252
  21. 3783
  22. 9408
  23. 15680
  24. 72
  25. 30450
  26. 54571
  27. 65709
  28. 9975
  29. 33488
  30. 18612
  31. 11904
  32. 9216
  33. 5296
  34. 864
  35. 62192
  36. 37926
  37. 72500
  38. 25002
  39. 765
  40. 34496

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