Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 228 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 17200 people. The population grows by 15% every year. What will the population be after 1 year?
2. 2.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹57700 at 10% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹12500 grow to in 2 years at 10% per year compound interest (in ₹)?
5. 5.What amount will ₹8400 grow to in 2 years at 10% per year compound interest (in ₹)?
6. 6.A town has 41000 people. The population grows by 10% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹30000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
9. 9.Find the compound interest on ₹53200 at 25% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
11. 11.A town has 5100 people. The population grows by 20% every year. What will the population be after 1 year?
12. 12.A town has 12500 people. The population grows by 4% every year. What will the population be after 2 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹42600 at 10% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹15600 at 25% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹4200 at 25% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹12400 at 20% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹39000 at 20% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹45400 grow to in 2 years at 10% per year compound interest (in ₹)?
20. 20.A scooter is worth ₹27800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹52600 at 10% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹11600 at 5% per year for 2 years, compounded every year (in ₹).
23. 23.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹6100 at 10% per year for 1 year, compounded every year (in ₹).
25. 25.A scooter is worth ₹38000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
26. 26.Find the compound interest on ₹22800 at 25% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 11200 people. The population grows by 5% every year. What will the population be after 2 years?
28. 28.What is the difference between the compound interest and the simple interest on ₹13200 at 20% per year for 2 years (in ₹)?
29. 29.A town has 46500 people. The population grows by 20% every year. What will the population be after 3 years?
30. 30.A scooter is worth ₹40000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
31. 31.A scooter is worth ₹58000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹15600 at 15% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹33900 at 25% per year for 1 year, compounded every year (in ₹).
34. 34.Find the compound interest on ₹36100 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹13600 at 5% per year for 2 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
37. 37.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
38. 38.What amount will ₹29700 grow to in 1 year at 12% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹52800 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹36200 at 12% per year for 1 year, compounded every year (in ₹).

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