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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 229 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  2. 2.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
  3. 3.Find the compound interest on ₹34800 at 25% per year for 2 years, compounded every year (in ₹).
  4. 4.What amount will ₹49500 grow to in 1 year at 4% per year compound interest (in ₹)?
  5. 5.A town has 8000 people. The population grows by 5% every year. What will the population be after 1 year?
  6. 6.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  7. 7.What amount will ₹8600 grow to in 1 year at 5% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  10. 10.What amount will ₹28200 grow to in 1 year at 12% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
  12. 12.A scooter is worth ₹7000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  13. 13.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹42500 grow to in 2 years at 12% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹8800 at 5% per year for 2 years, compounded every year (in ₹).
  17. 17.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
  18. 18.What amount will ₹17400 grow to in 1 year at 12% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹4400 at 4% per year for 1 year, compounded every year (in ₹).
  20. 20.A scooter is worth ₹51400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹8700 at 10% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
  23. 23.What amount will ₹10900 grow to in 1 year at 20% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹37500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  25. 25.Find the compound interest on ₹17600 at 8% per year for 1 year, compounded every year (in ₹).
  26. 26.A town has 32800 people. The population grows by 5% every year. What will the population be after 2 years?
  27. 27.What amount will ₹56000 grow to in 1 year at 15% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
  29. 29.What amount will ₹25800 grow to in 2 years at 20% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹4800 at 20% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹48900 grow to in 1 year at 20% per year compound interest (in ₹)?
  33. 33.A scooter is worth ₹10600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹29800 at 20% per year for 2 years (in ₹)?
  35. 35.Find the compound interest on ₹33600 at 15% per year for 2 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹43200 at 15% per year for 2 years (in ₹)?
  37. 37.What amount will ₹36600 grow to in 1 year at 12% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  39. 39.What amount will ₹4200 grow to in 1 year at 10% per year compound interest (in ₹)?
  40. 40.A town has 17200 people. The population grows by 25% every year. What will the population be after 2 years?

Answer key

  1. 9826
  2. 59895
  3. 19575
  4. 51480
  5. 8400
  6. 9152
  7. 9030
  8. 1261
  9. 36
  10. 31584
  11. 1224
  12. 6300
  13. 18522
  14. 656
  15. 53312
  16. 902
  17. 40560
  18. 19488
  19. 176
  20. 41634
  21. 87
  22. 35075
  23. 13080
  24. 29040
  25. 1408
  26. 36162
  27. 64400
  28. 1071
  29. 37152
  30. 192
  31. 1230
  32. 58680
  33. 10070
  34. 1192
  35. 10836
  36. 972
  37. 40992
  38. 8334
  39. 4620
  40. 26875

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