Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 2.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹34800 at 25% per year for 2 years, compounded every year (in ₹).
- 4.What amount will ₹49500 grow to in 1 year at 4% per year compound interest (in ₹)?
- 5.A town has 8000 people. The population grows by 5% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
- 7.What amount will ₹8600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 10.What amount will ₹28200 grow to in 1 year at 12% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
- 12.A scooter is worth ₹7000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 13.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
- 15.What amount will ₹42500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹8800 at 5% per year for 2 years, compounded every year (in ₹).
- 17.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
- 18.What amount will ₹17400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 19.Find the compound interest on ₹4400 at 4% per year for 1 year, compounded every year (in ₹).
- 20.A scooter is worth ₹51400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹8700 at 10% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
- 23.What amount will ₹10900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 24.A scooter is worth ₹37500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 25.Find the compound interest on ₹17600 at 8% per year for 1 year, compounded every year (in ₹).
- 26.A town has 32800 people. The population grows by 5% every year. What will the population be after 2 years?
- 27.What amount will ₹56000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
- 29.What amount will ₹25800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹4800 at 20% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹12000 at 5% per year for 2 years, compounded every year (in ₹).
- 32.What amount will ₹48900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 33.A scooter is worth ₹10600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹29800 at 20% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹33600 at 15% per year for 2 years, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹43200 at 15% per year for 2 years (in ₹)?
- 37.What amount will ₹36600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 39.What amount will ₹4200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 40.A town has 17200 people. The population grows by 25% every year. What will the population be after 2 years?
Answer key
- 9826
- 59895
- 19575
- 51480
- 8400
- 9152
- 9030
- 1261
- 36
- 31584
- 1224
- 6300
- 18522
- 656
- 53312
- 902
- 40560
- 19488
- 176
- 41634
- 87
- 35075
- 13080
- 29040
- 1408
- 36162
- 64400
- 1071
- 37152
- 192
- 1230
- 58680
- 10070
- 1192
- 10836
- 972
- 40992
- 8334
- 4620
- 26875
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