Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 234 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹59000 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.A scooter is worth ₹22700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.A scooter is worth ₹25000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.Find the compound interest on ₹52500 at 4% per year for 1 year, compounded every year (in ₹).
6. 6.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹4500 at 25% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹3400 grow to in 1 year at 12% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹12000 at 15% per year for 2 years, compounded every year (in ₹).
11. 11.A town has 5000 people. The population grows by 10% every year. What will the population be after 3 years?
12. 12.What amount will ₹30500 grow to in 2 years at 10% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹59400 at 4% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹42300 grow to in 1 year at 4% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹57200 at 15% per year for 2 years, compounded every year (in ₹).
17. 17.A scooter is worth ₹52400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
18. 18.A town has 21500 people. The population grows by 20% every year. What will the population be after 3 years?
19. 19.Find the compound interest on ₹28000 at 20% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 27500 people. The population grows by 10% every year. What will the population be after 1 year?
21. 21.What is the difference between the compound interest and the simple interest on ₹29600 at 25% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹38000 at 15% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹51100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
24. 24.Find the compound interest on ₹47700 at 4% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹58500 grow to in 3 years at 20% per year compound interest (in ₹)?
26. 26.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
27. 27.What amount will ₹10000 grow to in 3 years at 20% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
29. 29.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
30. 30.A scooter is worth ₹45300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
31. 31.A town has 51300 people. The population grows by 10% every year. What will the population be after 2 years?
32. 32.What amount will ₹46700 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.A town has 32700 people. The population grows by 8% every year. What will the population be after 1 year?
34. 34.A scooter is worth ₹36700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
35. 35.A scooter is worth ₹55100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹22000 at 20% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 58300 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
40. 40.A town has 14000 people. The population grows by 15% every year. What will the population be after 2 years?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets