Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 235 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹26500 grow to in 1 year at 4% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹13900 at 12% per year for 1 year, compounded every year (in ₹).
3. 3.Find the compound interest on ₹15600 at 15% per year for 2 years, compounded every year (in ₹).
4. 4.What amount will ₹30400 grow to in 2 years at 25% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹29800 at 10% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹23200 at 25% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹31000 at 20% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹15400 at 15% per year for 1 year, compounded every year (in ₹).
9. 9.What amount will ₹19100 grow to in 1 year at 8% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹27200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
11. 11.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹18800 at 25% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹2400 at 15% per year for 2 years (in ₹)?
15. 15.What amount will ₹13400 grow to in 1 year at 10% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹14900 at 10% per year for 2 years (in ₹)?
17. 17.What amount will ₹37400 grow to in 1 year at 10% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹30500 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.A scooter is worth ₹18400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
21. 21.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹55300 at 20% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹58400 at 15% per year for 2 years (in ₹)?
24. 24.What amount will ₹5600 grow to in 1 year at 12% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹40900 at 20% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹28100 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 5500 people. The population grows by 20% every year. What will the population be after 2 years?
29. 29.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.A town has 2500 people. The population grows by 20% every year. What will the population be after 3 years?
32. 32.Find the compound interest on ₹9600 at 25% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹20700 grow to in 1 year at 15% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹38000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
39. 39.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.A town has 49400 people. The population grows by 10% every year. What will the population be after 2 years?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets