Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 236 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹38100 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹59000 at 15% per year for 1 year, compounded every year (in ₹).
5. 5.What amount will ₹32800 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.A scooter is worth ₹7800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
7. 7.A town has 59200 people. The population grows by 25% every year. What will the population be after 3 years?
8. 8.A town has 58000 people. The population grows by 15% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹27600 at 10% per year for 1 year, compounded every year (in ₹).
10. 10.What amount will ₹46600 grow to in 2 years at 20% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹13900 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹37000 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹15800 at 25% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹9000 at 10% per year for 2 years (in ₹)?
15. 15.A scooter is worth ₹10100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
16. 16.Find the compound interest on ₹53200 at 5% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 57200 people. The population grows by 5% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹35700 at 10% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹5400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
21. 21.Find the compound interest on ₹29900 at 4% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 10000 people. The population grows by 15% every year. What will the population be after 2 years?
23. 23.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
24. 24.What amount will ₹56000 grow to in 2 years at 5% per year compound interest (in ₹)?
25. 25.What amount will ₹16600 grow to in 1 year at 15% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹48200 at 10% per year for 2 years (in ₹)?
27. 27.What amount will ₹13800 grow to in 1 year at 20% per year compound interest (in ₹)?
28. 28.What amount will ₹3000 grow to in 1 year at 4% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
30. 30.A scooter is worth ₹20500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
33. 33.What amount will ₹11800 grow to in 1 year at 12% per year compound interest (in ₹)?
34. 34.What amount will ₹59800 grow to in 1 year at 4% per year compound interest (in ₹)?
35. 35.A town has 28400 people. The population grows by 20% every year. What will the population be after 2 years?
36. 36.What amount will ₹49600 grow to in 1 year at 20% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹4000 at 20% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹60000 at 10% per year for 2 years (in ₹)?
40. 40.A town has 26500 people. The population grows by 20% every year. What will the population be after 3 years?

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