Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 237 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹27600 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
4. 4.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹56600 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹19000 at 25% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹40800 grow to in 1 year at 15% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
10. 10.What amount will ₹14900 grow to in 2 years at 20% per year compound interest (in ₹)?
11. 11.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
12. 12.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
15. 15.A town has 28300 people. The population grows by 10% every year. What will the population be after 2 years?
16. 16.Find the compound interest on ₹23000 at 4% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹16400 at 5% per year for 2 years, compounded every year (in ₹).
18. 18.A town has 46400 people. The population grows by 25% every year. What will the population be after 3 years?
19. 19.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹17200 at 25% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹49700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹12400 at 15% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹23600 at 5% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹30100 at 20% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹56000 at 10% per year for 3 years, compounded every year (in ₹).
27. 27.A town has 45000 people. The population grows by 10% every year. What will the population be after 3 years?
28. 28.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹11600 at 10% per year for 2 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
34. 34.What amount will ₹42200 grow to in 1 year at 20% per year compound interest (in ₹)?
35. 35.What amount will ₹29600 grow to in 1 year at 10% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹34100 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹44600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹15500 at 10% per year for 2 years (in ₹)?
40. 40.What amount will ₹11700 grow to in 1 year at 25% per year compound interest (in ₹)?

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