Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹27800 at 25% per year for 1 year, compounded every year (in ₹).
- 2.Find the compound interest on ₹36000 at 20% per year for 3 years, compounded every year (in ₹).
- 3.A scooter is worth ₹42800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 4.What amount will ₹28300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 5.What amount will ₹48400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 8.A town has 31200 people. The population grows by 5% every year. What will the population be after 2 years?
- 9.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 10.Find the compound interest on ₹10700 at 10% per year for 1 year, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹13200 at 25% per year for 2 years (in ₹)?
- 12.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹46000 at 15% per year for 2 years (in ₹)?
- 14.What amount will ₹12300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 15.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
- 16.Find the compound interest on ₹9000 at 10% per year for 1 year, compounded every year (in ₹).
- 17.Find the compound interest on ₹11300 at 25% per year for 1 year, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹5300 at 20% per year for 2 years (in ₹)?
- 19.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 20.A town has 31800 people. The population grows by 5% every year. What will the population be after 1 year?
- 21.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 22.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 23.What amount will ₹56200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 24.A town has 50400 people. The population grows by 15% every year. What will the population be after 2 years?
- 25.Find the compound interest on ₹39200 at 15% per year for 2 years, compounded every year (in ₹).
- 26.What amount will ₹51900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 27.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
- 28.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 29.Find the compound interest on ₹18800 at 15% per year for 2 years, compounded every year (in ₹).
- 30.What amount will ₹50400 grow to in 2 years at 10% per year compound interest (in ₹)?
- 31.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 32.A scooter is worth ₹43200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 33.Find the compound interest on ₹38200 at 20% per year for 1 year, compounded every year (in ₹).
- 34.A town has 18900 people. The population grows by 10% every year. What will the population be after 2 years?
- 35.What is the difference between the compound interest and the simple interest on ₹12900 at 20% per year for 2 years (in ₹)?
- 36.A town has 6100 people. The population grows by 25% every year. What will the population be after 1 year?
- 37.A scooter is worth ₹21500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 38.Find the compound interest on ₹54100 at 10% per year for 1 year, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?
Answer key
- 6950
- 26208
- 34668
- 29715
- 58080
- 12501
- 180
- 34398
- 29624
- 1070
- 825
- 2916
- 1035
- 13530
- 68992
- 900
- 2825
- 212
- 61236
- 33390
- 13718
- 56250
- 59010
- 66654
- 12642
- 62799
- 52488
- 48013
- 6063
- 60984
- 6859
- 18225
- 7640
- 22869
- 516
- 7625
- 11008
- 5410
- 36
- 342
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