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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 249 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹27800 at 25% per year for 1 year, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹36000 at 20% per year for 3 years, compounded every year (in ₹).
  3. 3.A scooter is worth ₹42800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  4. 4.What amount will ₹28300 grow to in 1 year at 5% per year compound interest (in ₹)?
  5. 5.What amount will ₹48400 grow to in 1 year at 20% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  8. 8.A town has 31200 people. The population grows by 5% every year. What will the population be after 2 years?
  9. 9.A scooter is worth ₹35000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  10. 10.Find the compound interest on ₹10700 at 10% per year for 1 year, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹13200 at 25% per year for 2 years (in ₹)?
  12. 12.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹46000 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹12300 grow to in 1 year at 10% per year compound interest (in ₹)?
  15. 15.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
  16. 16.Find the compound interest on ₹9000 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹11300 at 25% per year for 1 year, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹5300 at 20% per year for 2 years (in ₹)?
  19. 19.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
  20. 20.A town has 31800 people. The population grows by 5% every year. What will the population be after 1 year?
  21. 21.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  22. 22.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
  23. 23.What amount will ₹56200 grow to in 1 year at 5% per year compound interest (in ₹)?
  24. 24.A town has 50400 people. The population grows by 15% every year. What will the population be after 2 years?
  25. 25.Find the compound interest on ₹39200 at 15% per year for 2 years, compounded every year (in ₹).
  26. 26.What amount will ₹51900 grow to in 2 years at 10% per year compound interest (in ₹)?
  27. 27.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
  28. 28.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  29. 29.Find the compound interest on ₹18800 at 15% per year for 2 years, compounded every year (in ₹).
  30. 30.What amount will ₹50400 grow to in 2 years at 10% per year compound interest (in ₹)?
  31. 31.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  32. 32.A scooter is worth ₹43200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  33. 33.Find the compound interest on ₹38200 at 20% per year for 1 year, compounded every year (in ₹).
  34. 34.A town has 18900 people. The population grows by 10% every year. What will the population be after 2 years?
  35. 35.What is the difference between the compound interest and the simple interest on ₹12900 at 20% per year for 2 years (in ₹)?
  36. 36.A town has 6100 people. The population grows by 25% every year. What will the population be after 1 year?
  37. 37.A scooter is worth ₹21500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  38. 38.Find the compound interest on ₹54100 at 10% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹15200 at 15% per year for 2 years (in ₹)?

Answer key

  1. 6950
  2. 26208
  3. 34668
  4. 29715
  5. 58080
  6. 12501
  7. 180
  8. 34398
  9. 29624
  10. 1070
  11. 825
  12. 2916
  13. 1035
  14. 13530
  15. 68992
  16. 900
  17. 2825
  18. 212
  19. 61236
  20. 33390
  21. 13718
  22. 56250
  23. 59010
  24. 66654
  25. 12642
  26. 62799
  27. 52488
  28. 48013
  29. 6063
  30. 60984
  31. 6859
  32. 18225
  33. 7640
  34. 22869
  35. 516
  36. 7625
  37. 11008
  38. 5410
  39. 36
  40. 342

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